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Leokris [45]
3 years ago
10

Write the name of the first twenty elements with their symbols and their atomic number​

Chemistry
2 answers:
7nadin3 [17]3 years ago
6 0

Answer:

1 Hydrogen H

2 Helium He

3 Lithium Li

4 Beryllium Be

5 Boron B

6 Carbon C

7 Nitrogen N

8 Oxygen O

9 Fluorine F

10 Neon Ne

11 Sodium Na

12 Magnesium Mg

13 Aluminium Al

14 Silicon Si

15 Phosphorus P

16 Sulfur S

17 Chlorine Cl

18 Argon Ar

19 Potassium K

20. calcium Ca

Archy [21]3 years ago
3 0

Answer:

h - hydrogen (1)

he - helium (2)

li - lithium (3)

be - beryllium (4)

b - boron (5)

c - carbon (6)

n - nitrogen (7)

o - oxygen (8)

f - fluorine (9)

ne - neon (10)

na - sodium (11)

mg - magnesium (12)

al- aluminium (13)

si - silicon (14)

p - phosphorus (15)

s - sulfur (16)

cl - chlorine (17)

ar - argon (18)

k - potassium (19)

ca - calcium (20)

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Deduce the molecular formula of hydrogen 18.2%, carbon 81.8%, relative molecular mass is 44​
ivanzaharov [21]

Answer:

let number of carbon is an

Explanation:

hence 12 and + 2n is equal to 126

14 and is equal to 126

n is equal to 9

7 0
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When air expands what type of energy increases?
LuckyWell [14K]
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4 moles of monoatomic ideal gas is compressed adiabatically causing the temperature to increase from 300 K to 400 K. Calculate t
yawa3891 [41]

Answer:

the work done on the gas is 4,988.7 J.

Explanation:

Given;

number of moles of the monoatomic gas, n = 4 moles

initial temperature of the gas, T₁ = 300 K

final temperature of the gas, T₂ = 400 K

The work done on the gas is calculated as;

W = \Delta U = nC_v(T_2 -T_1)

For monoatomic ideal gas: C_v = \frac{3}{2} R

W = \frac{3}{2} R \times n(T_2-T_1)

Where;

R is ideal gas constant = 8.3145 J/K.mol

W = \frac{3}{2} R \times n(T_2-T_1) \\\\W = \frac{3}{2} (8.3145) \times 4(400-300) \\\\W =  \frac{3}{2} (8.3145) \times 4(100)\\\\W = 4,988.7 \ J

Therefore, the work done on the gas is 4,988.7 J.

4 0
3 years ago
Have a good day today:) 100 free pts!
Naddik [55]

:o really? thank you so much!

5 0
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