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Leokris [45]
3 years ago
10

Write the name of the first twenty elements with their symbols and their atomic number​

Chemistry
2 answers:
7nadin3 [17]3 years ago
6 0

Answer:

1 Hydrogen H

2 Helium He

3 Lithium Li

4 Beryllium Be

5 Boron B

6 Carbon C

7 Nitrogen N

8 Oxygen O

9 Fluorine F

10 Neon Ne

11 Sodium Na

12 Magnesium Mg

13 Aluminium Al

14 Silicon Si

15 Phosphorus P

16 Sulfur S

17 Chlorine Cl

18 Argon Ar

19 Potassium K

20. calcium Ca

Archy [21]3 years ago
3 0

Answer:

h - hydrogen (1)

he - helium (2)

li - lithium (3)

be - beryllium (4)

b - boron (5)

c - carbon (6)

n - nitrogen (7)

o - oxygen (8)

f - fluorine (9)

ne - neon (10)

na - sodium (11)

mg - magnesium (12)

al- aluminium (13)

si - silicon (14)

p - phosphorus (15)

s - sulfur (16)

cl - chlorine (17)

ar - argon (18)

k - potassium (19)

ca - calcium (20)

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. Sulfur dioxide can be produced in the laboratory by the reaction of hydrochloric acid and a sulfite salt such as sodium sulfit
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Answer:

Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g

Explanation:

SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.

        the balanced chemical equation is as follows

                       Na₂SO₃ + 2 HCl → 2 NaCl + SO₂ + H₂O

Moles of Na₂SO₃ = \frac{Mass}{Molecular mass} =\frac{25}{126} = 0.198

Moles of HCl = \frac{mass}{molecular mass}=\frac{22}{36.5}= 0.6

using mole ratio method to find limiting reagent

      For sodium sulfite \frac{mole}{stoichiometry}  = \frac{0.198}{1}= 0.198

 for HCl \frac{mole}{stoichiometry}  = \frac{0.6}{2}= 0.3

since <u>sodium sulfite</u> is <u>limiting reactant</u> for above chemical reaction

1 mole of Na₂SO₃ produce 1 mole of SO₂

0.198 mole of Na₂SO₃ produce 0.198 mole of SO₂

∴ Mass of SO₂ produce = mole x molar mass of SO₂

                                       = 0.198 x 64

                                       = 12.672 g

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