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Leokris [45]
2 years ago
10

Write the name of the first twenty elements with their symbols and their atomic number​

Chemistry
2 answers:
7nadin3 [17]2 years ago
6 0

Answer:

1 Hydrogen H

2 Helium He

3 Lithium Li

4 Beryllium Be

5 Boron B

6 Carbon C

7 Nitrogen N

8 Oxygen O

9 Fluorine F

10 Neon Ne

11 Sodium Na

12 Magnesium Mg

13 Aluminium Al

14 Silicon Si

15 Phosphorus P

16 Sulfur S

17 Chlorine Cl

18 Argon Ar

19 Potassium K

20. calcium Ca

Archy [21]2 years ago
3 0

Answer:

h - hydrogen (1)

he - helium (2)

li - lithium (3)

be - beryllium (4)

b - boron (5)

c - carbon (6)

n - nitrogen (7)

o - oxygen (8)

f - fluorine (9)

ne - neon (10)

na - sodium (11)

mg - magnesium (12)

al- aluminium (13)

si - silicon (14)

p - phosphorus (15)

s - sulfur (16)

cl - chlorine (17)

ar - argon (18)

k - potassium (19)

ca - calcium (20)

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What is the volume in a 2. 00M solution containing 8.00 moles of solute?
MrMuchimi

Answer:

4000cm³

Explanation:

2.0moles-1000cm³

8.0moles-?

(8.0×1000)÷2

=4000cm³

5 0
3 years ago
What step is ussaly done right before the experimentation in the scientific method
barxatty [35]

The Step that is Usually done right before the experimentation in the Scientific Method is Developing a Hypothesis and asking a Question.

Hope that helped!

~Izzy


3 0
3 years ago
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Which of the following samples contains the greatest number of atoms?
mart [117]

Answer:

C. 11 moles of N2O

Explanation:

A. CO2 exists as a molecular compound. The number of atoms present = 1 atom of Carbon and 2 atoms oxygen = 3 atoms * 9 = 18 atoms

B. Xe exists as an atom. Number of atoms present = 10 * 1 atom = 10 atoms

C. N20 contains 3 atoms; 2 atoms of Nitrogen and 1 atom of oxygen.

Number of atoms present = 3 * 11 = 33 atoms

D. CO contains 2 atoms, 1 each of carbon and oxygen.

Number of atoms present = 12 * 2 = 24 atoms

7 0
3 years ago
How would you abbreviate you as an element?​
qaws [65]

Answer:

i am unique and have a specific number in the periodic table

5 0
3 years ago
If you feed 100 kg of N2 gas and 100 kg of H2 gas into a
torisob [31]

Answer : The mass of ammonia produced can be, 121.429 k

Solution : Given,

Mass of N_2 = 100 kg  = 100000 g

Mass of H_2 = 100 kg = 100000 g

Molar mass of N_2 = 28 g/mole

Molar mass of H_2 = 2 g/mole

Molar mass of NH_3 = 17 g/mole

First we have to calculate the moles of N_2 and H_2.

\text{ Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molar mass of }N_2}=\frac{100000g}{28g/mole}=3571.43moles

\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{100000g}{2g/mole}=50000moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

N_2+3H_2\rightarrow 2NH_3

From the balanced reaction we conclude that

As, 1 mole of N_2 react with 3 mole of H_2

So, 3571.43 moles of N_2 react with 3571.43\times 3=10714.29 moles of H_2

From this we conclude that, H_2 is an excess reagent because the given moles are greater than the required moles and N_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NH_3

From the reaction, we conclude that

As, 1 mole of N_2 react to give 2 mole of NH_3

So, 3571.43 moles of N_2 react to give 3571.43\times 2=7142.86 moles of NH_3

Now we have to calculate the mass of NH_3

\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3

\text{ Mass of }NH_3=(7142.86moles)\times (17g/mole)=121428.62g=121.429kg

Therefore, the mass of ammonia produced can be, 121.429 kg

6 0
3 years ago
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