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SashulF [63]
3 years ago
15

Molar mass of osmium

Chemistry
1 answer:
lidiya [134]3 years ago
7 0

Answer:-

190.23 gram mol-1

Explanation:-

Molar mass is the mass of 1 mole of that substance. It's unit is gram / mol or gram mol-1.

For an element it is equal to it's atomic weight.

The atomic weight of Osmium is 190.23

Hence the molar mass of Osmium is 190.23 gram / mol

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What happened to the FREQUENCY of the wave as the instrument got bigger?
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Answer:

The wavelengths at which resonance occurs are proportional to the length of the instrument, so you can play different notes by changing the length. In general the larger the instrument the longer the wavelength of the fundamental and the lower the frequency range of the instrument.

Explanation:

4 0
3 years ago
A device that does work with only one movement is a simple machine <br> true or false
Rainbow [258]

Answer:

true

Explanation:

8 0
3 years ago
Which option is an element <br> A: carbon dioxide <br> B: Water <br> C: Air<br> D: Carbon
Ivenika [448]

Answer:

D: Carbon

Explanation:

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3 0
3 years ago
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What is the percentage composition when 10g of magnesium combines with 4g of nitrogen?
Ivanshal [37]
The %  composition   when 10g of magnesium combine   with  4g of   nitrogen  is  71.43%   magnesium   and  28.57 %  nitrogen

               calculation

%
  composition  =  mass  of an element  / total mass  x100
mass  of magnesium = 10 g
mass of nitrogen  =  4g

calculate  the  total  mass  used

=  10g of  Magnesium  + 4 g of  nitrogen = 14 grams

%   composition for  magnesium  is therefore  =  10/14  x100 = 71.43 %

%  
composition  for  nitrogen  is therefore = 4 /14  x100  =   28.57 %
7 0
3 years ago
How many liters of 1.5 M potassium permanganate could be made if 152 g of the solute are available?
Misha Larkins [42]

Answer:

0.64 L

Explanation:

Recall that

n= CV where n=m/M

Hence:

m/M= CV

m= given mass of solute =152g

M= molar mass of solute

C= concentration of solute in molL-1 = 1.5M

V= volume of solute =????

Molar mass of potassium permanganate= 158.034 g/mol

Thus;

152 g/158.034 gmol-1= 1.5M × V

V= 0.96/1.5

V= 0.64 L

6 0
3 years ago
Read 2 more answers
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