Answer:
The answer to your question is 9.075 g of CO₂
Explanation:
Data
mass of C₃H₈ = 39 g
mass of O₂ = 11 g
Balanced chemical reaction
C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂
-Calculate the molar mass of the reactants
C₃H₈ = (12 x 3) + (8 x 1) = 36 + 8 = 44 g
O₂ = (16 x 2) = 32 g
-Calculate the limiting reactant
theoretical yield C₃H₈ / O₂ = 44/5(32) = 44/ 160 = 0.275
experimental yield C₃H₈/O₂ = 39/11 = 3.5
From the previous result, we conclude that the limiting reactant is O₂ because the experimental yield was higher than the theoretical yield.
-Calculate the mass of CO₂
160 g of O₂ ----------------- 3(44) g of CO₂
11 g of O₂ ------------------ x
x = (11 x 3(44)) / 160
x = 1452 / 160
x = 9.075 g of CO₂
