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xxMikexx [17]
3 years ago
14

C3H8+5O2 →3CO2+4H2

Chemistry
1 answer:
Lisa [10]3 years ago
3 0

Answer:

The answer to your question is 9.075 g of CO₂

Explanation:

Data

mass of C₃H₈ = 39 g

mass of O₂ = 11 g

Balanced  chemical reaction

                C₃H₈  +  5O₂  ⇒  3CO₂  +  4H₂

-Calculate the molar mass of the reactants

C₃H₈ = (12 x 3) + (8 x 1) = 36 + 8 = 44 g

O₂ = (16 x 2) = 32 g

-Calculate the limiting reactant

theoretical yield  C₃H₈ / O₂ = 44/5(32) = 44/ 160 = 0.275

experimental yield C₃H₈/O₂ = 39/11 = 3.5

From the previous result, we conclude that the limiting reactant is O₂ because the experimental yield was higher than the theoretical yield.

-Calculate the mass of CO₂                

             160 g of O₂ ----------------- 3(44) g of CO₂

               11 g of O₂ ------------------  x

                    x = (11 x 3(44)) / 160

                    x = 1452 / 160

                    x = 9.075 g of CO₂

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At the Henry's Law constant for carbon dioxide gas in water is . Calculate the mass in grams of gas that can be dissolved in of
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The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

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<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

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C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M

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\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

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Volume of solution = 425 mL

Putting values in above equation, we get:

0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g

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Answer:

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