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sveticcg [70]
3 years ago
12

Help please asap!!

Chemistry
1 answer:
In-s [12.5K]3 years ago
8 0
<span>Saturated hydrocarbon cannot bond with compounds anymore, where as unsaturated hydrocarbons can bond, as they contain double or triple bonds. When they bond, the double and triple bonds break and new separate single bonds are formed with hydrogens or any other external compounds</span>
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natka813 [3]

Answer:

A scale, or a weight. Both of which are more scientifically referred to as a balance.

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In which block of the periodic table should iron be placed
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Iron should be in the 3d block

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Standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (v) au3 (aq) 3e−→au(s) 1.50 fe2 (aq) 2e−→f
Zanzabum

<em>K</em> = 5.0 × 10^25

<h2>Part (a). Calculate <em>E</em>° for the reaction </h2>

<em>Step 1.</em> Write the equations for the two half-reactions

2H^(+)(aq) + 2e^(-) → H2(g); _0.00 V

Zn^(2+)(aq) + 2e^(-) → Zn(s); -0.76 V

<em>Step 2.</em> Identify the cathode and the anode

The half-cell with the more negative <em>E</em>° (Zn) is the anode.

<em>Step 3.</em> Calculate <em>E</em>°

Zn(s) → Zn^(2+)(aq) + 2e^(-); _________+0.76 V

2H^(+)(aq) + 2e^(-) → H2(g); __________0.00 V

Zn(s) + 2H^(+)(aq) → Zn^(2+)(aq) + H2(g); +0.76 V

<em>E</em>° = +0.76 V

<h2>Part (b). Calculate <em>K</em> for the reaction </h2>

The relation between <em>E</em>° and <em>K</em> is

<em>E</em>° = (<em>RT</em>)/(<em>nF</em>)ln<em>K </em>

where

<em>R</em> = the universal gas constant: 8.314 J·K^(-1)mol^(-1)

<em>T</em> = the Kelvin temperature

<em>n</em> = the moles of electrons transferred

<em>F</em> = the Faraday constant: 96 485 J·V^(-1)mol^(-1)

Then

0.76 V = [8.314 J·K^(-1)mol^(-1) × 298.15 K]/[2 × 96 485 J·V^(-1)mol^(-1)]ln<em>K</em>

0.76 = 0.012 85 ln<em>K</em>

ln<em>K</em> = 0.76/0.012 85 = 59.16

<em>K</em> =e^59.16 = 5.0 × 10^25

4 0
3 years ago
One way to determine the degree of saturation of a solid-liquid solution is to drop a crystal of the solute into the solution.
Dafna1 [17]

The answer is D: Saturated.

A saturated solution is one in which the exact maximum amount of solute has been dissolved.  So, new solute will not dissolve in the solution.  In contrast, an unsaturated solution can hold more solute, so if that option were correct, the crystal would have dissolved.

The other two terms are a bit more complicated.  A supersaturated solution is one holding an amount of solute above the sustainable limit.  Because of that, when more solute is added, the solution will immediately adjust, and some solute will come out of solution in a precipitate.  Because the crystal isn't growing, we can eliminate this option.

A concentrated solution is one holding a relatively large amount of solute.  However, you can have concentrated solutions that are saturated and unconcentrated (the word for this is dilute) solutions that aren't saturated.  Therefore, we can say that because the crystal doesn't dissolve, this solution is saturated, but we can't say with certainty that it is concentrated.

Because the first three options are invalid, as described above, while the scenario does describe a saturated solution, D is the correct answer.

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Nadusha1986 [10]

Answer:

First, you have to analyze your problem or question. After you research and collect data about your topic, create a hypothesis to test to try and find the answer. After testing your hypothesis, come up with a conclusion based on the results.

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