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aliya0001 [1]
3 years ago
11

What is the easiest character to play in smash personally I like cloud if anybody can tell me any combos for him I’ll give brain

liest
Engineering
2 answers:
Alina [70]3 years ago
8 0

But to answer your question on easy character i say rob he has a very good recovery good down throw good combos to get u from zero to 60 and has his spin to win plus laser and disk he can zone attack and if u side b someone off stage you can try to side b them again and it will kill thats if u land it though

Helga [31]3 years ago
5 0

Answer: Go the OG route pick classic Mario.

Explanation: Just cause

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The girls name on my phone I am in my name is
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3 years ago
An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions. If the
xenn [34]

Answer:C  0.12 V

Explanation:

Given

Concentration of Fe^{2+} M_1=0.40 M

Concentration of Ni^{2+} M_2=0.002 M

Standard Potential for Ni and Fe are V_2=-0.25 V  and V_1=-0.44 V

\Delta V=V_2-V_1-\frac{0.0592}{2}\log (\frac{M_1}{M_2})

\Delta V=-0.25-(-0.44)-\frac{0.0592}{2}\log (\frac{0.4}{0.002})

\Delta V=0.12\ V

7 0
3 years ago
Complete the following sentence.
Naya [18.7K]

Answer:

Communication

Explanation:

3 0
3 years ago
A well-established way of power generation involves the utilization of geothermal energy-the energy of hot water that exists nat
jeka94

Answer:

the maximum thermal efficiency is 29%

Explanation:

the maximum efficiency for a thermal engine that works between a cold source and a hot source is the one of a Carnot engine. Its efficiency is given by

Maximum efficiency= 1 - T2/T1

where

T2= absolute temperature of the cold sink (environment)= 20°C + 273 = 293

T2= absolute temperature of the hot source (hot water supply) = 140°C + 273 = 413

therefore

Maximum efficiency= 1 - T2/T1 = 1 - 293/413 = 0,29 =29%

3 0
3 years ago
You are working in a lab where RC circuits are used to delay the initiation of a process. One particular experiment involves an
Ymorist [56]

Answer:

t'_{1\2} = 6.6 sec

Explanation:

the half life of the given circuit is given by

t_{1\2} =\tau ln2

where [/tex]\tau = RC[/tex]

t_{1\2} = RCln2

Given t_{1\2} = 3 sec

resistance in the circuit is 40 ohm and to extend the half cycle we added new resister of 48 ohm. the net resitance is 40+48 = 88 ohms

now the new half life is

t'_{1\2} =R'Cln2

Divide equation 2 by 1

\frac{t'_{1\2}}{t_{1\2}} = \frac{R'Cln2}{RCln2} = \frac{R'}{R}

t'_{1\2} = t'_{1\2}\frac{R'}{R}

putting all value we get new half life

t'_{1\2} = 3 * \frac{88}{40}  = 6.6 sec

t'_{1\2} = 6.6 sec

7 0
3 years ago
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