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aleksandrvk [35]
3 years ago
9

Foundation dampproofing is most commonly installed: Select one: a. on both the inside and outside of the basement wall b. Baseme

nts do not need dampproofing beyond the basement wall itself c. on the inside of the basement wall d. on the outside of the basement wall
Engineering
1 answer:
puteri [66]3 years ago
4 0

Answer:A

Explanation:

Damp roof is generally applied at basement level which restrict the movement of moisture through walls and floors. Therefore it could be inside or the outside basement walls.

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The link acts as part of the elevator control for a small airplane. If the attached aluminum tube has an inner diameter of 25 mm
aksik [14]

Answer:

Tmax=14.5MPa

Tmin=10.3MPa

Explanation:

T = 600 * 0.15 = 90N.m

T_max =\frac{T_c}{j}  = \frac{x}{y}  = \frac{90 \times 0.0175}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}

=14.5MPa

T_{min} =\frac{T_c}{j}  = \frac{x}{y}  = \frac{90 \times 0.0125}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}

=10.3MPa

7 0
3 years ago
Steam at 75 kPa and 8 percent quality is contained in a spring-loaded piston–cylinder device, as shown in Figure, with an initia
Rashid [163]

The heat transferred to and the work produced by the steam during this process  is 13781.618 kJ/kg

<h3>​How to calcultae the heat?</h3>

The Net Change in Enthalpy will be:

= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg

Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)

= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

From the First Law of Thermodynamics, Q = U + W

So, Heat Transfer = Change in Internal Energy + Work Done

= 13331.618 + 450

Q = 13781.618 kJ/kg

Learn more about heat on:

brainly.com/question/13439286

#SP1

6 0
1 year ago
A) For Well A, provide a cross-section sketch that shows (i) ground elevation, (ii) casing height, (iii) depth to
Ad libitum [116K]
Don’t go on that file will give a virus! Sorry just looking out and I don’t know how to comment!
7 0
3 years ago
4. The outer end of a control arm is attached to the steering knuckle through a
arlik [135]
Is attached to the spring
3 0
3 years ago
Read 2 more answers
Train levels a station and travels north at 60km/hr. Two hours later, a second train leaves on a parallel track and travels nort
Amanda [17]

Answer: they would be 300 miles from the station.

Explanation:

At the point where both trains meet, they would have covered the same distance.

Let t represent the time spent by the first train in covering this distance.

Distance = speed × time

The first train leaves the station and travels north at 60km/hr.

Distance covered by the first train is

60 × t = 60t

Two hours later, a second train leaves on a parallel track and travels north at 100km/hr. Time spent by the second train in covering this distance is (t - 2) hours

Distance covered by the second train is

100(t - 2) = 100t - 200

Since both trains covered the same distance, then

100t - 200 = 60t

100t - 60t = 200

40t = 200

t = 200/40

t = 5 hours

The distance that they would be from the station is

60 × 5 = 300 miles

6 0
3 years ago
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