The heat transferred to and the work produced by the steam during this process is 13781.618 kJ/kg
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How to calcultae the heat?</h3>
The Net Change in Enthalpy will be:
= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg
Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)
= 1/2 x ( 75 + 225) x (5 - 2)
W = 450 KJ
From the First Law of Thermodynamics, Q = U + W
So, Heat Transfer = Change in Internal Energy + Work Done
= 13331.618 + 450
Q = 13781.618 kJ/kg
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Don’t go on that file will give a virus! Sorry just looking out and I don’t know how to comment!
Answer: they would be 300 miles from the station.
Explanation:
At the point where both trains meet, they would have covered the same distance.
Let t represent the time spent by the first train in covering this distance.
Distance = speed × time
The first train leaves the station and travels north at 60km/hr.
Distance covered by the first train is
60 × t = 60t
Two hours later, a second train leaves on a parallel track and travels north at 100km/hr. Time spent by the second train in covering this distance is (t - 2) hours
Distance covered by the second train is
100(t - 2) = 100t - 200
Since both trains covered the same distance, then
100t - 200 = 60t
100t - 60t = 200
40t = 200
t = 200/40
t = 5 hours
The distance that they would be from the station is
60 × 5 = 300 miles