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ladessa [460]
3 years ago
11

The VLBA (Very Long Baseline Array) uses a number of individual radio telescopes to make one unit having an equivalent diameter

of about 8000 km. This radio telescope is focusing radio waves of wavelength 2.0 cm. What would have to be the diameter of the mirror of a visible-light telescope focusing light of wavelength 582 nm so that the visible-light telescope has the same resolution as the radio telescope? Give an answer in m. Pay attention to the number of significant figures.
Physics
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

d₂=232.8 m

Explanation:

We know that formula for resolution given as

θres = 1.22 λ/d

Where

λ=wavelength

d=diameter

Given that resolution should be same.So we can say that

1.22 λ₁/d₁= 1.22 λ₂/d₂

λ₁/d₁= λ₂/d₂

d_2=\dfrac{\lambda _2}{\lambda _1}d_1

Given that

λ₂=582 nm

λ₁=2 cm

d₁=8000 km

d_2=\dfrac{582\times 10^{-9}\times 8000\times10^3}{0.02}\ m

d₂=232.8 m

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6 0
1 year ago
1. A runner has an initial speed of 2 [m/s] and slowly speeds up with a constant acceleration of
zvonat [6]

Answer:

Final Velocity = 4.9 m/s

Explanation:

We are given;. Initial velocity; u = 2 m/s

Constant Acceleration; a = 0.1 m/s²

Distance; s = 100 m

To find the final velocity(v), we will use one of Newton's equations of motion;

v² = u² + 2as

Plugging in the relevant values to give;

v² = 2² + 2(0.1 × 100)

v² = 4 + 20

v² = 24

v = √24

v = 4.9 m/s

5 0
2 years ago
A uniform magnetic field passes through a horizontal circular wire loop at an angle 15.1 ° from the normal to the plane of the l
umka2103 [35]

Answer:

Magnetic flux through the loop is 1.03 T m²

Explanation:

Given:

Magnetic field, B = 4.35 T

Radius of the circular loop, r = 0.280 m

Angle between circular loop and magnetic field, θ = 15.1⁰

Magnetic flux is determine by the relation:

\Phi = BA\cos \theta   ....(1)

Here A represents area of the circular loop.

Area of circular loop, A = πr²

Hence, the equation (1) becomes:

\Phi=B\pi r^{2} \cos \theta

Substitute the suitable values in the above equation.

\Phi=4.35\times\pi (0.28)^{2} \cos 15.1

\Phi = 1.03 T m²

8 0
2 years ago
If
nadya68 [22]

Answer:

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Explanation:

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8 0
3 years ago
Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker poi
Nataly [62]

Answer

given,

mass of ball, m = 57.5 g = 0.0575 kg

velocity of ball northward,v = 26.7 m/s

mass of racket, M = 331 g = 0.331 Kg

velocity of the ball after collision,v' = 29.5 m/s

a) momentum of ball before collision

   P₁ = m v

   P₁ = 0.0575 x 26.7

   P₁ = 1.535 kg.m/s

b) momentum of ball after collision

   P₂ = m v'

   P₂ = 0.0575 x (-29.5)

   P₂ = -1.696 kg.m/s

c) change in momentum

    Δ P = P₂ - P₁

    Δ P = -1.696 -1.535

    Δ P = -3.231 kg.m/s

d) using conservation of momentum

  initial speed of racket = 0 m/s

  M u + m v = Mu' + m v

  M x 0 + 0.0575 x 26.7 = 0.331 x u' + 0.0575 x (-29.5)

  0.331 u' = 3.232

     u' = 9.76 m/s

change in velocity of the racket is equal to 9.76 m/s

5 0
3 years ago
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