Answer:
45.165× 10²³ NH₄⁺ ions
Explanation:
Given data:
Number of NH₄⁺ ions present = ?
Moles of (NH₄)₃PO₄ = 2.5 mol
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
1 mole of (NH₄)₃PO₄ = 3 mole NH₄⁺
In 2.5 moles of (NH₄)₃PO₄ = 2.5× 3 = 7.5 moles of NH₄⁺
Number of ions of NH₄⁺ in 2.5 moles of (NH₄)₃PO₄:
7.5 mole of NH₄⁺ × 6.022 × 10²³ NH₄⁺ ions / 1 mol
45.165× 10²³ NH₄⁺ ions
I think the answer is A but I could be wrong
It is both a and b
nuclear rxns will ALWAYS have changes in both mass and some of that mass will be converted into energy.
One of the major events is Volcanos etc...
The word identity is a mistake. The question asks for the density of a cube of metal with the measures and mass given.
Density = mass / volume
mass = 35.45 g
volume of a cube = (length of the side) ^ 3 = (1.5 cm)^3 = 3.375 cm^3
Density = 35.45 g / 3.375 cm^3 = 10.50 g / cm^3.
Answer: 10.50 g / cm^3