Question

Calculate the frequency of photon 434E-9 and speed of light 3E8m/s

Answer 1

Answer:

f = 6.912 E14 Hz

Explanation:

The speed of the wave is defined as

speed = wavelength*frequency

the frequency of the photon  is defined as

f = speed / wavelength

f = 3 E8 m/s / 434 E-9 m

f = 6.912 E14 Hz

Answer 2

Answer:

Frequency,  $f=6.91\times 10^{14}\ Hz$

Explanation:

It is given that,

Wavelength, $\lambda=434\times 10^{-9}\ m$

Speed of light, $c=3\times 10^8\ m/s$

The frequency of photon can be calculated using following relation as :

$c=f\times \lambda$

$f=\dfrac{c}{\lambda}$

$f=\dfrac{3\times 10^8\ m/s}{434\times 10^{-9}}$

$f=6.91\times 10^{14}\ Hz$

So, the frequency of the photon is $f=6.91\times 10^{14}\ Hz$. Hence, this is the required solution.