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stira [4]
3 years ago
11

Find the magnitude of the electric field due to a charged ring of radius "a" and total charge "Q", at a point on the ring axis a

distance "a" from the ring's center.
Physics
1 answer:
34kurt3 years ago
4 0

Answer:

E=\frac{KQ}{2\sqrt 2a^2}

Explanation:

We are given that

Charge on ring= Q

Radius of ring=a

We have to find the magnitude of electric filed on the axis at distance a from the ring's center.

We know that the electric field at distance x from the center of ring of radius R is given by

E=\frac{kQx}{(R^2+x^2)^{\frac{3}{2}}}

Substitute x=a and R=a

Then, we get

E=\frac{KQa}{(a^2+a^2)^{\frac{3}{2}}}

E=\frac{KQa}{(2a^2)^{\frac{3}{2}}}

E=\frac{KQa}{2\sqrt 2a^3}

E=\frac{KQ}{2\sqrt 2a^2}

Where K=9\times 10^9 Nm^2/C^2

Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=\frac{KQ}{2\sqrt 2a^2}

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Anon25 [30]
Metallic bonds! Hope this helps!! :))
3 0
2 years ago
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05. The time required to complete one lap around a perfectly circular track having a radius of 1,835 meters is 86
likoan [24]

Answer:

v = 134.06 m/s

Explanation:

Given that,

Radius of a circular track is 1,835 m

Time required to complete one lap around a perfectly circular track is 86 seconds

We need to find the car's velocity. Velocity is equal to,

v=d/t

On circular path,

v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 1835}{86}\\\\v=134.06\ m/s

So, car's velocity is 134.06 m/s.

7 0
3 years ago
What is the displacement of a car in 50 s if it is travelling with a velocity of 25 m/s?
Schach [20]

Answer:

v =25 m/s

time= 50 s

Velocity =Displacement/Time

Displacement = Velocity × Time

S = 25×50

s=1250m

Explanation:

v =25 m/s

time= 50 s

Velocity =Displacement/Time

Displacement = Velocity × Time

7 0
2 years ago
Shane is riding his bike at a speed of 10m/s. He isn't watching carefully where he is going and almost hit a tree. He abruptl
Rom4ik [11]

Answer:

2.5m/s²

Explanation:

a = v/t

Where;

V = velocity (m/s)

a = acceleration (m/s²)

t = time (s).

According to the information provided in this question,

a = ?

v = 10m/s

t = 4

a = 10/4

a = 2.5m/s²

4 0
2 years ago
The lightest and heaviest flying birds are the bee hummingbird of Cuba, which weighs about 1.6 grams, and the great bustard of E
VMariaS [17]

Answer:

for the birds to be able to stay vertical in flight without falling down to earth, they must produce a lift that will counteract their weight

for the small bee humming bird,

mass = 1.6 g = 1.6 x 10^{-3}  kg

weight of the bird under acceleration due to gravity = mg

where g = acceleration due to gravity = 9.81 m/s^2

weight of the bird = 1.6 x 10^{-3}  x 9.806 = 0.0156 ≅ 0.016 N

for this bird to maintain flight, the least lift upward, it must generate must be equal to its weight downwards, i.e

lift = weight

therefore,

lift = <em>0.016 N</em>

<em></em>

For the bustard of Europe and Asia,

mass = 21 kg

weight of the bird under acceleration due to gravity = mg

weight of the bird = 21 x 9.806 = 205.9 N

lift = weight =  <em>205.9 N</em>

<em></em>

<em>lift generated is proportional to the wing surface area according to the lift equation</em>

L = Cs x p x \frac{v}{2} x S

where L = lift

C = lift coefficient

p = density of air

v = relative velocity of bird and air

S = surface are of the wing.

<em>The great bustard will have a proportionally larger wing area to hold its weight in flight</em>

<em></em>

7 0
3 years ago
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