U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you
The displacement volume in liters is 2.74 liters.
<h3>What is displacement volume?</h3>
Displacement volume is the quantity of solvent that will be displaced by a specified quantity of a solid during dissolution.
It can also be defined as the volume displaced by the piston as it moves between top dead center and bottom dead center in a car engine.
<h3>Displacement volume in liters</h3>
1 liter = 61.02 in³
? = 167 in³
= 167/61.02
= 2.74 liters
Thus, the displacement volume in liters is 2.74 liters.
Learn more about displacement volume here: brainly.com/question/1945909
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Answer:
it will take 36.12 ms to reduce the capacitor's charge to 10 μC
Explanation:
Qi= C×V
then:
Vi = Q/C = 30μ/20μ = 1.5 volts
and:
Vf = Q/C = 10μ/20μ = 0.5 volts
then:
v = v₀e^(–t/τ)
v₀ is the initial voltage on the cap
v is the voltage after time t
R is resistance in ohms,
C is capacitance in farads
t is time in seconds
RC = τ = time constant
τ = 20µ x 1.5k = 30 ms
v = v₀e^(t/τ)
0.5 = 1.5e^(t/30ms)
e^(t/30ms) = 10/3
t/30ms = 1.20397
t = (30ms)(1.20397) = 36.12 ms
Therefore, it will take 36.12 ms to reduce the capacitor's charge to 10 μC.
Answer: THE ANSWER IS C!
The total energy of a system can decrease only if energy leaves the system.
Explanation: Apex!