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Maslowich
3 years ago
6

: Suppose you’re trying to measure an unknown sensor resistance, ????????????????????o???? , by converting it to a voltage. For

a fixed set of values of ????1 ,????1 ,???????????? and ????????????, each of the following circuits will yield an output voltage, ????o , as function of ????????????????????o???? . a. [10 points] For each of these circuits, write the equations relating ????o to ????????????????????o???? . b. [10 points] Find the sensitivity for each of these circuits (note that the sensitivities for some of these circuits may not be constants).
Engineering
1 answer:
statuscvo [17]3 years ago
7 0

Answer:

(a) R₁ / (R₁ + R_{sensor})

(b) -R_{sensor} / (R₁ + R_{sensor})

Explanation:

(a)

i - Using voltage division rule =

v₀ = v₁ [R_{sensor} / (R₁+R_{sensor})]

The sensitivity is

ii - \int\limits^{vo}_{Rsensor} = dv₀/dR_{sensor}  *  R_{sensor}/v₀

                = R₁ / (R₁ + R_{sensor})

(b)

i - Using voltage divisor rule = v₀ = v₁ [R_{sensor} / (R₁+R_{sensor})]

ii - \int\limits^{vo}_{Rsensor} =  dv₀/dR_{sensor}  *  R_{sensor}/v₀

               = -R_{sensor} / (R₁ + R_{sensor})

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An ideal gas initially at 300 K and 1 bar undergoes a three-step mechanically reversible cycle in a closed system. In step 12, p
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A clear details for the question is also attached.

(b) The P,V and T for state 1,2 and 3

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=

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14

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9.49 barr

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569.5 K

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(c) For step 12: Isothermal, Since AT = 0 then AH12 = AU12 = 0 and

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Now from first law of thermodynamic the Q23

AU2s = Q23= 5601.55

Mol

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Now from first law of thermodynamie the Ws1

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AUs¡ = Ws¡ = -5601.55

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