Answer:
110 cm^2
Step-by-step explanation:
The first thing that you need to do is find the area of triangle AFE. The area of a triangle is always base*height/2. So in this case, that would be 10*6 divided by 2, which is 30 cm. Next, you will need to know the area of triangle ECB. Using that same formula, you will get 8*10/2, which is 40 cm. Finally, you will need to find the area of the whole rectangle. The area of a rectangle is always the length times the width. In this case, you would have 10*18, which is 180 cm. To get your final answer, you need to subtract the areas of the unshaded area from the whole area. That would be 180-(30+40), which is 110 cm. I hope this helped!
Answer:
Ones place
Step-by-step explanation:
9 in 976.14 is the hundreds place.
7 is the tens place.
6 is the ones place.
1 is the tenths place.
4 is the hundredths place.
You will flip the signs when you have to multiply or divide your equation by a negative integer.
Answer:
Step-by-step explanation:
a) To find the length of diagonal XT, we can use the distance formula to get 
Since this is a rectangle, XT=YW, meaning YW=10 as well.
b) The area of a rectangle is given by length times width. The length is |-3-5|=8, and the width is |-2-4|=6. So the area is (8)(6)=48.
c) The perimeter is just 2(8+6)=28.
Theoretical probability:
1 ... (16 and 2/3) %
2 ... (16 and 2/3) %
3 ... (16 and 2/3) %
4 ... (16 and 2/3) %
5 ... (16 and 2/3) %
6 ... (16 and 2/3) %
Experimental results:
1 ... 18
2 ... 16
3 ... 16
4 ... 17
5 ... 16
6 ... 17
The total number of rolls in the experiment was
(18 + 16 + 16 + 17 + 16 + 17) = 100
so the expected frequency for each outcome was 16-2/3 times,
and the SIMULATION probabilities were
1 ... 18%
2 ... 16%
3 ... 16%
4 ... 17%
5 ... 16%
6 ... 17%
To me, this looks fantastically close. The cube
could hardly be more fair than it actually is.
