When the entropy change of vaporization
= enthalpy of vaporization/boiling point temperature
when we have the enthalpy of vaporization = 38560 J/mol
and the boiling point temperature in Kelvin = 78.3 + 273 = 351.3 K
by substitution:
∴the entropy change of vaporization = 38560J/mol/351.3K
= 109.76 J/K/mol
and when the liquid has lesser entropy than the gas and we here convert from
gas to liquid so, the change in entropy = -109.76 J/K/mol
now, we need the moles of C2H5OH = mass/molar mass when the molar
mass of C2H5OH = 46 g/mol and mass = 42.2 g
∴ moles of C2H5OH = 42.2 g / 46 g/mol = 0.92 moles
when 1 mol of C2H5OH turns in liquid entropy change →-109.76 J/K/mol
∴ 0.92 mol of C2H5OH → X
∴ X entropy change when 0.92 mol = -109.76 *0.92 mol / 1 mol
= 84.64 J/K
The simplest unit factor that relates the number of hydrogen in sucrose to the number of oxygens is 1 O atom/ 2 H atoms.
Sucrose is a diasaccharide having the formula; C12H22O11.
This implies that there are twenty two atoms of hydrogen and eleven atoms of oxygen in a molecule of sucrose.
This gives a ratio of 2 hydrogen atoms to one oxygen atom. Therefore, the simplest unit factor that relates the number of hydrogen in sucrose to the number of oxygens is 1 O atom/ 2 H atoms.
Learn more: brainly.com/question/11347582
C. the square root of the mass of the particles.
<h3>Further explanation </h3>
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:

or

From this equation shows that the greater the mass of the gas, the smaller the effusion rate of the gas and vice versa, the smaller the mass of the gas, the greater the effusion velocity.
So if both gases are at the same temperature and pressure, the above formula can apply
Salt water is a Homogeneous Mixture......