Data:
M (Molar Mass) of C2H6
C = 2*12 = 24 amu
H = 6*1 = 6 amu
---------------------
MM C2H6 = 24+6 = 30 g/mol
P (pressure) = 1.6 atm
V (volume) = 12.7 L
<span>R = 0,082 atm .L/mol.K
n (</span>Number of mols) →
![n = \frac{m}{MM} m (mass) = ? T = 24ºC Celsius to Kelvin TK = TºC + 273 TK = 24 + 273 TK = 297 By the equation of state of the gases or equation of Clapeyron, we have: [tex]P*V = n*R*T](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Bm%7D%7BMM%7D%20m%20%28mass%29%20%3D%20%3F%20T%20%3D%2024%C2%BAC%20%20Celsius%20to%20Kelvin%20TK%20%3D%20T%C2%BAC%20%2B%20273%20TK%20%3D%2024%20%2B%20273%20TK%20%3D%20297%20%20%20%3Cspan%3EBy%20the%20equation%20of%20state%20of%20the%20gases%20or%20equation%20of%20Clapeyron%2C%20we%20have%3A%0A%20%20%20%3C%2Fspan%3E%5Btex%5DP%2AV%20%3D%20n%2AR%2AT%20)
<span>
Since </span>

<span>, we can perform the following substitution in the above Clapeyron equation:
</span>


multiply cross

Solving:




Answer:
25.03 grams of ethane gas
Answer:
<h3>The answer is 3 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula

From the question we have

We have the final answer as
<h3>3 g/cm³</h3>
Hope this helps you
Answer:
<em><u>Decomposition reactions are processes in which chemical species break up into simpler parts. Usually, decomposition reactions require energy input. For example, a common method of producing oxygen gas in the laboratory is the decomposition of potassium chlorate (KClO3) by heat.</u></em>
Explanation:
hope it will help u
Answer:
option C= 12.40
Explanation:
Formula:
pH + pOH = 14
First of all we will calculate the pH.
pH = - log [H⁺]
pH = - log [0.025]
pH = - (-1.6)
pH = 1.6
Now we will put the values in formula,
pH + pOH = 14
pOH = 14-pH
pOH = 14 -1.6
pOH = 12.4
The pOH of solution is 12.4.
Answer:
<h2>3.18 × 10²³ atoms</h2>
Explanation:
The number of atoms can be found by using the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.529 × 6.02 × 10²³
We have the final answer as
<h3>3.18 × 10²³ atoms</h3>
Hope this helps you