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3 years ago

A carousel is spinning at a speed of 100 cm/s, with the outermost horse at a distance 5 m from the center.

1 answer:

5 0

The speed is 100/100=1 meter per second, so acceleration is 1^2/5=.2. Then, the net force is 0.2*1.5 kg = 0.3 N, or 3*10^-1 N.

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A starter pistol is fired 150m away from the spectators who hear the gun 0.5s after they see it fired. How fast does sound trave

Natali [406]

Answer:

300m/s

Explanation:

speed = distance/time

150/0.5

8 0

3 years ago

a 150 newton force acts on a 300kg cars calculate how long it takes this force to change the car's velocity from 2m/s to 6m/s

Sedaia [141]

Answer:8

Explanation:f=m*a

150=300*v-u/t

=150=300*6-2/t

4/t=150/300

t=4*2

t=8

hope this helps

mark me brainliest

3 0

3 years ago

Read 2 more answers

In a longitudinal wave, the places where particles of matter are closer together called

Blizzard [7]

Explanation:

I hesitate to articulate upon the highest degree of accuracy!

5 0

4 years ago

The severity of a fall depends on your speed when you strike the ground. All factors but the acceleration from gravity being the

Diano4ka-milaya [45]

Answer:

<em>The object could fall from six times the original height and still be safe</em>

Explanation:

<u>Free Falling</u>

When an object is released from rest in free air (no friction), the motion is completely dependant on the acceleration of gravity g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy of

$U=m.g.h$

When the object strikes the ground, all the mechanical energy (only potential energy) becomes into kinetic energy

$\displaystyle K=\frac{1}{2}m.v^2$

Where v is the speed just before hitting the ground

If we know the speed v is safe for the integrity of the object, then we can know the height it was dropped from

$\displaystyle m.g.h=\frac{1}{2}m.v^2$

Solving for h

$\displaystyle h=\frac{m.v^2}{2mg}=\frac{v^2}{2g}$

If the drop had occurred in the Moon, then

$\displaystyle h_M=\frac{v_M^2}{2g_M}$

Where hM, vM and gM are the corresponding parameters on the Moon. We know v is the safe hitting speed and the gravitational acceleration on the Moon is g_M=1/6 g

$\displaystyle h_M=\frac{v^2}{2\frac{1}{6}g}$

$\displaystyle h_M=6\frac{v^2}{2g}=6h$

This means the object could fall from six times the original height and still be safe

6 0

4 years ago

The resistance of a light bulb that draws a current of 2 a when connected t a 12 v battery is?

8090 [49]

Explanation:

$V = I *R$

where:

V is the voltage

I is the current

R is the resistance

Rearranging, we have:

$R = \frac{V}{I} = \frac{12}{2}$ = ?

7 0

4 years ago