1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
a_sh-v [17]
3 years ago
15

the smallest unit in physics is the Planet length.wr need to know constant (h) the speed of light (c) and Newton's Gravitational

Constant ( G). Find the Planck Length.
Physics
2 answers:
fgiga [73]3 years ago
4 0

Yes, that's right.  It's the 'Planck' length, not the 'Planet' length.

You could easily find these with a web search.  But in gratitude
for the bountiful 5 points, I've saved you the trouble. 
AND guess what !   By doing that, I learned something, and
you didn't.

Speed of light (c):                 299,792,458 meters per second

Gravitational constant (G):   6.67 x 10⁻¹¹  newton-meter²/kilogram²

Planck's Konstant (h):           6.63 x 10⁻³⁴ joule-second

Planck Length:                      1.6 x 10⁻³⁵ meter
                                            (about 10⁻²⁰ the size of a proton)

Planck Time:                          10⁻⁴³ second
                                             (about the time it takes to travel
                                              a Planck Length at the speed of light)  

den301095 [7]3 years ago
4 0
Planck length is the going to be the smallest unit of measure known. The speed of light is a constant, the universes speed "limit". Although quantum entanglement beat that speed, but it doesn't threaten the speed of light since the process doesn't hold information. And that was from my own knowledge of the information I soak up daily in college education on the path to a PhD in physics.
You might be interested in
to 10 Hz. Superimposed on this signal is 60-Hz noise with an amplitude of 0.1 V. It is desired to attenuate the 60-Hz signal to
givi [52]

Answer:

G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1

If we square both sides we got:

G^2 (1+\frac{f}{f_c})^{2n}= 1

We divide both sides by G^2 and we got:

(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}

Now we can apply log on both sides and we got:

2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})

And solving for n we got:

n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}

And replacing we got:

n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}

n = \frac{4.60517}{3.8918}=1.18

And since n needs to be an integer the correct answer would be n=2 for the filter order.

Explanation:

For this case we can use the formula for the Butterworth filter gain given by:

[tec] G = \frac{1}{\sqrt{1 +(\frac{f}{f_c})^{2n}}}[/tex]

Where:

G represent the transfer function and we want that G =0.1 since the desired signal is less than 10% of it's value

f_c = 10 Hz represent the corner frequency

f= 60 Hz represent the original frequency

n represent the filter order and that's the variable that we need to find

G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1

If we square both sides we got:

G^2 (1+\frac{f}{f_c})^{2n}= 1

We divide both sides by G^2 and we got:

(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}

Now we can apply log on both sides and we got:

2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})

And solving for n we got:

n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}

And replacing we got:

n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}

n = \frac{4.60517}{3.8918}=1.18

And since n needs to be an integer the correct answer would be n=2 for the filter order.

7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Yuki888 [10]

7. 1.47 x 10^5mm to kilometers

Answer: 0.147

Shown answer:


8.4.7 kg to pounds

Answer:

Shown answer:

9.138.4oz to grams

Answer: 3923.574

Shown Answer:


10. 65.5km to miles

Answer: 40.69981

Shown answer:


11. 23.6ft to cm

Answer: 719.328

Shown answer:


12. 2.36 x 10^4 s to days

Answer: 0.273148148 days

Shown answer:


13. 13.6 L to U.S. Liquid quarts

Answer:

Shown answer:

show the work

help me and ill help you?

4 0
3 years ago
A massive tractor rolls down a country road. in a perfectly inelastic collision, a small sports car runs into the machine from b
Helga [31]
The answer for this change in the magnitude of momentum is the same for both because momentum is always conserved so both vehicles have the identical change. 
So for determining who has the greater change in kinetic energy, momentum (P) = mv so P^2 = m^2 v^2 P^2 / 2m = 1/2 m v^2 = energy So the weightier the mass the smaller the energy change for the same momentum change so in here, the car has a greater change in kinetic energy.
5 0
3 years ago
Read 2 more answers
What is 1 + 2 -3 +5 - 10​
e-lub [12.9K]
-5 is the correct answer for this!
5 0
3 years ago
When a student stands on a rotating table,the frictional force exerted on the student by the table is?
lakkis [162]

Answer:

Less

Explanation:

because static friction is more than rolling friction

7 0
3 years ago
Other questions:
  • you are sitting in a cart at the top of a hill on a roller coaster. you have 10,500 j of gravitational potential energy. if your
    7·1 answer
  • An ac generator consists of a coil with 40 turns of wire, each with an area of 0.06 m2. The coil rotates in a uniform magnetic f
    13·1 answer
  • A long non-conducting hollow cylinder with inner radius, ri and outer radius, r2 is charged with a uniform positive charge with
    7·1 answer
  • Harry and Hagrid needed to get money out of Gringotts bank. The bank cart was accelerating at a rate of 4 m/s2 and it had a mass
    15·1 answer
  • What is the speed of the 5 states of matter?
    7·1 answer
  • What is the common formula for work? Assume that W is the work, F is a constant force, 656-06-01-00-00_files/i0060000.jpgv is th
    10·1 answer
  • What is strain?
    15·1 answer
  • For Al, its atomic number is 13 and its mass number is 27. How many neutrons does it have?
    6·1 answer
  • White blood cells are most closely associated with which two body’s systems
    15·1 answer
  • A positively charged objectwith a mass of 0.114 kg oscillates at the end of a spring, generating ELF (extremely low frequency) r
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!