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3 years ago

How and why will my weight change if i took a trip to the moon

Physics

2 answers:

MatroZZZ [7]3 years ago

7 0

weight less on moon than on earth.

high on lift off - G force

low in orbit.

zero at a point between earth and moon

olganol [36]3 years ago

4 0

Answer:

Due to gravitational force

We know that,

weight (W) = m. g Newtons

Where m = mass , in Kg

g = gravitational force (m/s²)

= 9.8 m/s (it is constant on earth)

So, from equation we knew that Weight is proportional to the gravitational force assuming fixed mass.

On the moon the gravitational force (g) is very less compared to the earth gravitational force, i.e., 1.62 m/s²

Therefore from equation of weight W = m. g is very less by considering the gravitational force on moon.

So, obviously weight changes on moon due to gravitational pull

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An old light bulb draws only 54.3 W, rather than its original 60.0 W, due to evaporative thinning of its filament. By what facto

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Answer:

The factor of the diameter is 0.95.

Explanation:

Given that,

Power of old light bulb = 54.3 W

Power = 60 W

We know that,

The resistance is inversely proportional to the diameter.

$R\propto\dfrac{1}{D}$

The power is inversely proportional to the resistance.

$P\propto\dfrac{1}{R}$

$P\propto D^2$

We need to calculate the factor of the diameter of the filament reduced

Using relation of power and diameter

$\dfrac{P_{i}}{P_{f}}=\dfrac{D_{i}^2}{D_{f}^2}$

Put the value into the formula

$\dfrac{D_{i}^2}{D_{f}^2}=\dfrac{54.3}{60}$

$\dfrac{D_{i}}{D_{f}}=0.95$

$D_{i}=0.95 D_{f}$

Hence, The factor of the diameter is 0.95.

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