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Bess [88]
3 years ago
14

How and why will my weight change if i took a trip to the moon

Physics
2 answers:
MatroZZZ [7]3 years ago
7 0

weight less on moon than on earth.

high on lift off - G force

low in orbit.

zero at a point between earth and moon

olganol [36]3 years ago
4 0

Answer:

<em>Due to gravitational force</em>

We know that,

            weight (W) =  m. g  Newtons

            Where m = mass , in Kg

                        g = gravitational force (m/s²)

                           = 9.8 m/s (it is constant on earth)

        <em>  So, from equation we knew that Weight is proportional to the gravitational force assuming fixed mass.</em>

<em>       On the moon the gravitational force (g) is very less compared to the earth gravitational force, i.e., </em><em>1.62 m/s²</em>

<em>        Therefore from equation of weight</em><em> W = m. g</em><em> is very less by considering the gravitational force on moon.</em>

So, obviously weight changes on moon due to gravitational pull

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Doss [256]

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A magnet is used in a compass to show the direction.

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5 0
2 years ago
Read 2 more answers
A man walks 30 m to the west, then 5 m to the east in 45 seconds.
katen-ka-za [31]

Answer:

a. Displacement=30²+5²=925= 30.4m

b. Total distance=30m+5m=35m

c. V=s/t. = 30.4/45=0.6m/s

8 0
1 year ago
The 60.0 kg skier shown below is skiing down a 35.0 degree incline where the magnitude of the friction force is 38.5N
Sunny_sXe [5.5K]

Answer:

a) 4.98m/s²

b) 481.66N

Explanation:

a) Using the Newtons second law of motion

\sum F_x = ma_x\\F_m - F_f = ma_x\\Wsin \theta - F_f = ma_x\\mgsin \theta - F_f = ma_x\\

m is the mass of the object

g is the acceleration due to gravity

Fm is the moving force acting along the plane

Ff is the frictional force opposing the moving froce

a is the acceleration of the skier

Given

m = 60kg

g = 9.8m/s²

\theta = 35°

Ff = 38.5N

Required

acceleration of the skier a

Substituting into the formula;

60(9.8)sin 35^0 - 38.5 = 60a\\588sin35^0 - 38.5 = 60a\\337.26 - 38.5 = 60a\\298.76 = 60a\\a = 298.76/60\\a = 4.98m/s^2\\

Hence the acceleration of the skier is 4.98m/s²

b) The normal force on the skier is expressed as;

N = Wcosθ

N = mgcosθ

N = 60(9.8)cos 35°

N = 588cos 35°

N = 481.66N

Hence the normal force on the skier is 481.66N

5 0
3 years ago
Help me with this review question please.
QveST [7]

Answer:

K E=( mv²)/2

=(60×3.5²)/2

=367.5J

6 0
3 years ago
9. A constant velocity means acceleration is
vampirchik [111]

Answer:

d. zero

Explanation:

Constant velocity means the acceleration is zero. In this case the velocity does not change,

hope this helps you

have a good day :)

6 0
2 years ago
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