She does 200J .
We know she uses 20N of force and 10m is the distance. We multiply both numbers and we are given our answer of 200J. Hope this was helpful. :)
Answer:
they stick together when they get close
Vector trigonometry can be used for this problem. Since the horizontal component is 12 meters per second, this is technically the hypotenuse (actual initial velocity) multiplied to cosine of 40 degrees. Therefore, to find the hypotenuse, we must divide 12 by cosine 40degrees. cos(40)= 0.766, and 12/0.766 = approximately 15.664, therefore our answer is (3) 15.7 m/s
Answer:
If it has a mass of 5 kg its weight is 5 kg * 9.8 m/s^2 = 49 N
Weight in air = 49 N
Weight in water = 25 N
Buoyant force provided by water = 49 - 25 = 24 N