Two identical spheres a and b carry charges of +0.6 coulomb and -0.2 coulomb, respectively. If these spheres touch, the resultin
1 answer:
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The capacitance of the capacitor is
Explanation:
The capacitance of a parallel-plate capacitor is given by the equation
where
k is the dielectric constant of the medium
is the vacuum permittivity
A is the area of the plates
d is the separation between the plates
For the capacitor in this problem, we have:
k = 2.1 is the dielectric constant
is the separation between the plates
(I assumed that 5.4 m is a typo, since it is not a realistic size for the side of the plate)
Therefore, the capacitance of the capacitor is
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Answer:
110.9 m/s²
Explanation:
Given:
Distance of the tack from the rotational axis (r) = 37.7 cm
Constant rate of rotation (N) = 2.73 revolutions per second
Now, we know that,
1 revolution = radians
So, 2.73 revolutions =
Therefore, the angular velocity of the tack is,
Now, radial acceleration of the tack is given as:
Plug in the given values and solve for . This gives,
Therefore, the radial acceleration of the tack is 110.9 m/s².