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The total power delivered by the battery if the lightbulbs are connected is 9V^2/R
<h3>Power of a battery</h3>
The formula for calculating the power of a battery is expressed according to the equation;
Power = v^2/RT
where
R is the total resistance
v is the voltage or emf
If there are 3 identical lightbulbs, each having constant resistance R, then;
1/RT = 1/R + 1/R + 1/R
1/RT = 3/R
RT = R/3
The voltage drop across each lightbulbs will be the same for parallel connection, hence;
Power = 3V^2/(R/3)
Power = 9V^2/R
Hence the total power delivered by the battery if the lightbulbs are connected is 9V^2/R
Learn more on power here: brainly.com/question/24858512
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Answer: We don’t really ever need to know how to dissect a frog but hey, one day maybe I’ll need to give a frog a discectomy
Answer:
101.54m/h
Explanation:
Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;
Let l be the be the distance further away at which they will meet from the current points;
#The speed toward each other.
Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h
Answer:
2 m/s
Explanation:
The first part of the question the car is going in reverse or negative along the x axis. Then the second part the car is moving forward along the x axis. So the car would only have velocity in the current direction of movement. So our equation for velocity is as follows.
v = d/t
v = 10 m/5 s
v = 2 m/s
