What quantity is represented by the slope of the graph?

The relative highness or lowness of a sound is called ______. Multiple Choice pitch timbre dynamics octave

Assoli18 [71]

Pitch is the answer…….

8 0

2 years ago

suppose your are looking at a yellow fish in a fish tank. the tank is next to a window. describe the path light takes in order f

Alex

The Sun --> through 93 million miles of space, in about 8 minutes --> through the Earth's atmosphere --> through the glass window into your house --> through a little more air, inside the room --> through the glass fishtank --> through some water --> light hits the fish; all colors of light except yellow get absorbed by the fish; the yellow waves bounce off --> through the water again --> through the glass tank again, out into the room --> through some air again --> a little bit of the yellow light happens to go into your eye, and you see it. Most of it doesn't, though.

3 0

3 years ago

__________ is the<br> process by which populations change over<br> time.

morpeh [17]

Evolution, is a process that results in changes in the genetic material of a population over time.

5 0

3 years ago

A 10.-kilogram object, starting at rest, slides down a frictionless incline with a constant acceleration of 2.0 ms for 40 second

Mashutka [201]

The velocity of the object after 4.0 seconds is 8.0 m/s

Explanation:

The motion of the object is a uniformly accelerated motion (constant acceleration), therefore we can use the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the object in this problem, we have:

u = 0 (it starts from rest)

$a=2.0m/s^2$ is the acceleration

t = 4.0 s is the time elapsed

Solving for v, we find the final velocity:

$v=0+(2.0)(4.0)=8.0 m/s$

Learn more about acceleration:

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#LearnwithBrainly

6 0

4 years ago

horizontal circular platform rotates counterclockwise about its axis at the rate of 0.919 rad/s. You, with a mass of 73.5 kg, wa

VARVARA [1.3K]

Answer:

The total angular momentum is 292.59 kg.m/s

Explanation:

Given that :

Rotation of the horizontal circular platform $\omega$ = 0.919 rad/s

mass of the platform (m) = 90.7 kg

radius (R) = 1.91 m

mass of the poodle $m_p$ = 20.5 kg

Your mass $m'$ = 73.5 kg

speed v = 1.05 m/s with respect to the platform

$V_p = \frac{1.05}{2} \ m /s \\ \\ = 0.525 \ m /s \\ \\r = \frac{R}{2}$

r = 0.955

Mass of the mutt $m_m$ = 18.5 kg

$r' = \frac{3}{4} \ R$

Your angular momentum is calculated as:

Your angular velocity relative to the platform is $\omega' = \frac{v}{R} = \frac{1.05}{1.91 } = 0.5497 \ rad/s$

$Actual \ \omega_y = \omega - \omega ' = (0.919 - 0.5497) \ rad/s = 0.3693 \ rad/s$

$I_y = m'R^2 = 73.5 *1.91^2= 268.14 \ kgm^2$

$L_Y = I_y*\omega_y= 268.14*0.3683= 98.76 \ kg.m/s$

For poodle :

$Relative \ \ \omega' = \frac{V_p}{R/2} = 0.550 \ rad/s$

Actual $\omega_p = \omega - \omega' = 0.919 -0.550 = 0.369 \ rad/s$

$I_p = m_p(\frac{R}{2} )^2 = 20.5(\frac{1.91}{2} )^2 = 18.70 \ kgm^2$

$L_p = I_p *\omega_p = 18.70*0.369 = 6.9003 \ kgm/s$

$I_M = m_m(\frac{3}{y4} R)^2 = 18.5 (\frac{3}{4} 1.91)^2 = 37.96 \ kgm^2$

$L_M = I_M \omega = 37.96 * 0.919= 34.89 \ kg.m/s$

Disk $I = \frac{mr^2}{2} = \frac{90.7*1.91^2}{2}= 165.44 \ kgm^2$

$L_D = I \omega = 165.44*0.919 =152.04 \ kg.m/s$

Total angular momentum of system is:

L = $L_D +L_Y+L_P+L_M$

= (152.04 + 98.76 + 6.9003 + 34.89) kg.m/s

= 292.59 kg.m/s

6 0

4 years ago