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stellarik [79]
3 years ago
15

If there is no angle on the plane wing you can't push the plane downward to create what? WILL GIVE BRAINLIEST PLS HELP

Physics
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer: i think the answer is lift

Explanation:

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A push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle θ below the horizontal,
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Answer:

its on wheels and they are supposed to make it eas

Explanation:

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Here is a graph of speed vs time. If the object is moving to the east, which BEST describes the speed and velocity of the graph?
san4es73 [151]

Answer: A JUST DID IT ON USA TESTPREP

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4. Two particles, A and B, are in uniform circular motion about a common center. The acceleration of particle A is 7.3 times tha
HACTEHA [7]

Answer:

Explanation:

Acceleration of particle A is 7.3 times the acceleration of particle B.

Let the acceleration of particle B is a, then the acceleration of particle A is

7.3 a.

Let the period of particle A is T and the period of particle B is 2.5 T.

Let the radius of particle A is RA and the radius of particle B is RB.

Use the formula for the centripetal force

a=r\omega ^{2}=r\times \frac{4\pi^{2}}{T^{2}}

So, r = a\frac{T^{2}}{4\pi^{2}}

The ratio of radius of A to the radius of B is given by

\frac{R_{A}}{R_{B}}=\frac{a_{A}\times T_{A}^{2}}{a_{B}\times T_{B}^{2}}

\frac{R_{A}}{R_{B}}=\frac{7.3 a\times T^{2}}{a\times 6.25T^{2}}

RA : RB = 1.17

3 0
3 years ago
Read 2 more answers
A spherical balloon is inflating with helium at a rate of 72 ft2/min . How fast is the​ balloon's radius increasing at the insta
Yanka [14]

The volume of the balloon is given by:

V = 4πr³/3

V = volume, r = radius

Differentiate both sides with respect to time t:

dV/dt = 4πr²(dr/dt)

Isolate dr/dt:

dr/dt = (dV/dt)/(4πr²)

Given values:

dV/dt = 72ft³/min

r = 3ft

Plug in and solve for dr/dt:

dr/dt = 72/(4π(3)²)

dr/dt = 0.64ft/min

The radius is increasing at a rate of 0.64ft/min

The surface area of the balloon is given by:

A = 4πr²

A = surface area, r = radius

Differentiate both sides with respect to time t:

dA/dt = 8πr(dr/dt)

Given values:

r = 3ft

dr/dt = 0.64ft/min

Plug in and solve for dA/dt:

dA/dt = 8π(3)(0.64)

dA/dt = 48.25ft²/min

The surface area is changing at a rate of 48.25ft²/min

7 0
3 years ago
Separate sheet of paper for your answer.
evablogger [386]

Answer:

I think its B. Please keep in mind that I could be wrong.

Explanation:

4 0
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