To solve this problem it is necessary to use the concepts related to the Hall Effect and Drift velocity, that is, at the speed that an electron reaches due to a magnetic field.
The drift velocity is given by the equation:
Where
I = current
n = Number of free electrons
A = Cross-Section Area
q = charge of proton
Our values are given by,
The hall voltage is given by
Where
B= Magnetic field
n = number of free electrons
d = distance
e = charge of electron
Then using the formula and replacing,
Before Pluto was discovered, it was predicted. Astronomers had observed that massive objects can affect the orbits of its neighbors, and, after seeing deviations in the orbits of Uranus and Neptune, assumed something substantial existed beyond their orbits.
When Pluto was spotted, it was thought to be the predicted object and was identified as a ninth planet.
A few decades later, astronomers started discovering more and more objects around other stars and didn’t know whether to call them planets or not. There appeared to be a need to define what a planet means, and that led to what some people consider Pluto’s demotion to a dwarf planet.
The International Astronomical Union decided that full-sized planets must orbit the sun, have a round shape, and have cleared their orbits of other objects. Pluto fulfills the first two criteria, but not the third.
It still goes around the sun, it’s round enough, it’s got moons, and behaves like a planet, but the idea is that Pluto did not form the same way as the rest of the planets. Pluto’s orbit is both eccentric and inclined more than the rest of the planets by about 17 degrees. That’s suggests something is different about this object.
This debate about whether to call it a planet or not is silly, because it doesn’t matter to Pluto what you call it. It is an interesting object, goes around the sun, and shows geology and an atmosphere.
There’s a tendency to define objects based on what they are now, but nothing is constant in the universe. There are some issues with the nomenclature, and a definition today may not apply to the same object tomorrow.
In order to work out this question, we must know the momentum of the marbles.
Marble 1 momentum:
Momentum1 = mass * velocity
Momentum1 = 5 * 5
Momentum1 = 25g cm/s.
Marble 2 momentum:
Momentum2 = mass * velocity
Momentum2 = 5 * 0
Momentum2 = 0g cm/s
Therefore, the total momentum of the marbles is equal to 25g cm/s.
Momentum is ALWAYS conserved in a collision! Meaning, the momentum before and after the marbles hit must be equal. Since marble 1 comes to a complete rest and there is no mention of a change in mass, Marble 2’s velocity must equal 5m/s due to conservation of momentum!
:)
Answer:
Explanation:
<em>Work </em>is the change in kinetic energy and may be calculated as the product of the force in the direction of the displacement times the displacement.
For a differential displacement, Δx, and a variable force, f(x), the differential work done is:
And the total work done from a point xi to xf is:
Thus, for this problem we have:
- f(x) =
The symbol is just indicating that the direction of the force is in the same direction of the displacement.
Integrating you get:
And that is 54.8697 joules (since the units for x are meter and the units for f(x) are newtons).
Rounded to two significant digits: 55 joules.
Answer:
Explanation:
Given that
I = a + b t
b = 14 A/s , h= 1 cm , w= 15 cm , L= 1.05 m
The magnitude of induced emf is given as follows
I = a + b t
Now by putting the values in the above equation we get
Thus the induce emf will be