An object in simple harmonic motion is observed to move between a maximum position and a minimum position.The minimum time that
2 answers:
Answer:c
Explanation:
When an object is performing simple harmonic motion then time period is given by measuring the time period take by object to return its initial position.
Thus we can say that it also valid for maximum position thus period is the correct is answer for this problem.
Time Period of oscillation for spring mass system is
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The question is incomplete. The complete question is :
Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.
What is the frequency of the sound?
Solution :
Given :
The distance between the two loud speakers,
The speaker are in phase and so the path difference is zero constructive interference occurs.
At the point , the speakers are out of phase and so the path difference is
Therefore,
Thus the frequency is :
Hz
Answer:
In terms of distance, average speed is 20 km/h
In terms of displacement, average speed is 0 km/h.
Explanation:
Total distance:
Total time is 3.0 hours
but:
In terms of distance.
substitute:
In terms of displacement: