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vodomira [7]
3 years ago
6

Use the portion of the periodic table shown below to answer the questions. A portion of the first three columns of the periodic

table is shown. Column one from top to bottom reads 11 sodium 22.990, 19 potassium 39.098, and 37 rubidium 85.468. Column two reads 12 magnesium 24.305, 20 calcium 40.078, and 38 strontium 87.62. Column three reads 21 scandium 44.956 and 39 yttrium 88.906. Part 1: Name two elements that have the same properties as calcium (Ca). (4 points) Part 2: Determine the number of protons, electrons, and neutrons present in an atom of sodium (Na). Explain how you determined your answer using complete sentences. (6 points)
Chemistry
2 answers:
Anna71 [15]3 years ago
7 0

I'm not sure about part 1, you may need to google it, but part two is 11 protons, 11 electrons and 12 neutrons. You can find protons and electrons by just looking at the atomic number, and you can find neutrons by subtracting the atomic number from the atomic mass.

Oxana [17]3 years ago
3 0

Answer:

1) magnesium and strontium

2) number of protons = 11

number of electrons = 11

number of neutrons = 12

Explanation:

Part 1:  

Two elements that have the same properties as calcium are magnesium and strontium. Elements in the same group (represented as columns in periodic table) share the same properties because they have the same number of electrons in the outermost electron shell.

Part 2:

For sodium, from the periodic table we know:

atomic number: 11

atomic mass: 22.990 ≈ 23

The number of protons and electrons is indicated by atomic number, in this case sodium has 11 protons and electrons (remember that atoms of the elements are electrically neutral, then they have the same amount of protons and electrons).

The mass of the atom is almost concentrated in the atomic nucleus, then the atomic mass represents the amount of protons and neutrons combined. So,

number of neutrons = atomic mass - atomic number = 23 - 11 = 12

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Sodium acetate can be formed from the metathesis/double replacement reaction of sodium
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Answer:

Explanation:

Sodium Acetate Trihydrate BP Specifications

Sodium Acetate BP

C2H3NaO2,3H2O

Action and use

Used in solutions for dialysis; excipient.

DEFINITION

Sodium ethanoate trihydrate.

Content

99.0 per cent to 101.0 per cent (dried substance).

CHARACTERS

Appearance

Colourless crystals.

Solubility

Very soluble in water, soluble in ethanol (96 per cent).

IDENTIFICATION

A. 1 ml of solution S (see Tests) gives reaction (b) of acetates.

B. 1 ml of solution S gives reaction (a) of sodium.

C. Loss on drying (As shown in the Relevant Test).

TESTS

Solution S

Dissolve 10.0 g in carbon dioxide-free water prepared from distilled water R and dilute to 100 ml 100 ml with the same solvent.

Appearance of solution

Solution S is clear and colourless.

pH

7.5 to 9.0.

Dilute 5 ml of solution S to 10 ml with carbon dioxide-free water.

Reducing substances

Dissolve 5.0 g in 50 ml of water, then add 5 ml of dilute sulphuric acid and 0.5 ml of 0.002 M potassium permanganate. The pink colour persists for at least 1 h. Prepare a blank in the same manner but without the substance to be examined.

Chlorides

Maximum 200 ppm.

Sulphates

Maximum 200 ppm.

Aluminium

Maximum 0.2 ppm, if intended for use in the manufacture of dialysis solutions.

Arsenic

Maximum 2 ppm, determined on 0.5 g.

Calcium and magnesium

Maximum 50 ppm, calculated as Ca.

Heavy metals

Maximum 10 ppm.

Iron

Maximum 10 ppm, determined on 10 ml of solution S.

Loss on drying

39.0 per cent to 40.5 per cent, determined on 1.000 g by drying in an oven at 130C.

Sodium Acetate FCC Food Grade, US Food Chemical Codex

C2H3NaO2 Formula wt, anhydrous 82.03

C2H3NaO2·3H2O Formula wt, trihydrate 136.08

DESCRIPTION

Sodium Acetate occurs as colorless, transparent crystals or as a granular, crystalline or white powder. The anhydrous form is hygroscopic; the trihydrate effloresces in warm, dry air. One gram of the anhydrous form dissolves in about 2 mL of water; 1 g of the trihydrate dissolves in about 0.8 mL of water and in about 19 mL of alcohol.

Function: Buffer.

REQUIREMENTS

Identification: A 1:20 aqueous solution gives positive tests for Sodium and for Acetate.

Assay: Not less than 99.0% and not more than 101.0% of C2H3NaO2 after drying.

Alkalinity Anhydrous: Not more than 0.2%; Trihydrate: Not more than 0.05%.

Lead: Not more than 2 mg/kg.

Loss on Drying: Anhydrous: Not more than 1.0%; Trihydrate: Between 36.0% and 41.0%.

Potassium Compounds: Passes test.

5 0
3 years ago
For a half-reaction in an acidic solution, which substances should you add to balance the equation?
solmaris [256]
Hello!

I believe the correct answer to this question is H+ and H2O.

I hope you found this helpful! :)
8 0
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