The equation described by the kb value is 5.21 x 
.
The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.
Assuming PO₄³⁻ (the phosphate anion).
PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻
Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]
We can find the [OH⁻] from the pH of 12.70.
pH + pOH = 14
14.0 - 12.7 = 1.3 = pOH
[OH] = 1x
[OH-] = 5.0x
M
[HPO₄²⁻] = 5.0x M
Kb = (5.0x)2 / 0.48
= 2.5x / 0.48
Kb = 5.21 x
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Answer:
The correct answer is: K'= 0.033.
Explanation:
The formation of HI from H₂ and I₂ is given by:
H₂ + I₂ → 2 HI K= 29.9
The decomposition of HI is the reverse reaction of the formation of HI:
2 HI → H₂ + I₂ K'
Thus, K' is the equilibrium constant for the reverse reaction of formation of HI. It is calculated as the reciprocal of the equilibrium constant of the forward reaction (K):
K' = 1/K = 1/(29.9)= 0.033
Therefore, the equilibrium constant for the decomposition of HI is K'= 0.033
Answer:
0.47V
Explanation:
2 Al(s) + 3 Mn2+(aq) → 2 Al3+(aq) + 3 Mn(s)
n= 6 ( six moles of electrons were transferred)
Q= [Red]/[Ox] but [Red]= 1.5M, [Ox] = 0.12 M
Q= 1.5/0.12= 12.5
From Nernst equation:
E= E°cell- 0.0592/n log Q
E°cell= 0.48 V
E= 0.48 - 0.0592/6 log (12.5)
E= 0.47V
There would be about 1.67 x 10^25 oxygen atoms and about 3.34 x 10^25 hydrogen atoms.
