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3 years ago

What is the acceleration of a car moving in a straight line at a constant velocity of 50 km/hr for 10 seconds?

Physics

1 answer:

Marysya12 [62]3 years ago

6 0

Constant velocity means no change in speed, so the acceleration is 0.

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Top-down processing is often used when one encounters an unfamiliar stimulus. Please select the best answer from the choices pro

Naddik [55]

The answer for this question would be B) False or the second option because top-down processing is NOT often used when one encounters an unfamiliar stimulus.

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3 years ago

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Nata [24]

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4 years ago

What has been happening to the cosmic microwave background radiation since the Big Bang?

kondor19780726 [428]

Answer:

Explanation:

Cosmologists refer to a "surface of last scattering" when the CMB photons last hit matter; after that, the universe was too big. So when we map the CMB, we are looking back in time to 380,000 years after the Big Bang, just after the universe was opaque to radiation. But the CMB was first found by accident.

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4 years ago

An object dropped from rest from the top of a tall building on planet x falls a distance d(t)18 left parenthesis t right parenth

melamori03 [73]

displacement is given by equation

$d = 18t^2$

now at t = 5 s the position is

$d_1 = 18 *5^2 = 450 m$

similarly position at t = 9 s

$d_2 = 18*9^2 = 1458 m$

so the displacement of object in given interval of time will be

$d = 1458 - 450 = 1008 m$

time interval

$\delta t = 9 - 5 = 4 s$

now the average velocity will be given as

$v = \frac{\delta x}{\delta t}$

$v = \frac{1008}{4} = 252 m/s$

so its average speed is 252 m/s

4 0

3 years ago

An object is moving along a straight line, and the uncertainty in its position is 1.90 m.

just olya [345]

Answer:

$2.78\times 10^{-35}\ \text{kg m/s}$

$6.178\times 10^{-34}\ \text{m/s}$

$0.31\times 10^{-4}\ \text{m/s}$

Explanation:

$\Delta x$ = Uncertainty in position = 1.9 m

$\Delta p$ = Uncertainty in momentum

h = Planck's constant = $6.626\times 10^{-34}\ \text{Js}$

m = Mass of object

From Heisenberg's uncertainty principle we know

$\Delta x\Delta p\geq \dfrac{h}{4\pi}\\\Rightarrow \Delta p\geq \dfrac{h}{4\pi\Delta x}\\\Rightarrow \Delta p\geq \dfrac{6.626\times 10^{-34}}{4\pi\times 1.9}\\\Rightarrow \Delta p\geq 2.78\times 10^{-35}\ \text{kg m/s}$

The minimum uncertainty in the momentum of the object is $2.78\times 10^{-35}\ \text{kg m/s}$

Golf ball minimum uncertainty in the momentum of the object

$m=0.045\ \text{kg}$

Uncertainty in velocity is given by

$\Delta p\geq m\Delta v\geq 2.78\times 10^{-35}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{m}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{0.045}\\\Rightarrow \Delta v\geq 6.178\times 10^{-34}\ \text{m/s}$

The minimum uncertainty in the object's velocity is $6.178\times 10^{-34}\ \text{m/s}$

Electron

$m=9.11\times 10^{-31}\ \text{kg}$

$\Delta v\geq \dfrac{\Delta p}{m}\\\Rightarrow \Delta v\geq \dfrac{2.78\times 10^{-35}}{9.11\times 10^{-31}}\\\Rightarrow \Delta v\geq 0.31\times 10^{-4}\ \text{m/s}$

The minimum uncertainty in the object's velocity is $0.31\times 10^{-4}\ \text{m/s}$ .

6 0

3 years ago