Answer: find the answer in the explanation
Explanation: The potential energy in a circuit between two points is the workdone in taking units positive charge from one point to the other in the circuit. Its S.I unit is Joule.
Because voltage of a battery or cell in a circuit is the potential energy difference across its terminal
The potential energy difference between two points is one volt, if the workdone in taking one Coulomb of positive charge from one point to the other is one Joule.
Yr average speed would be about 1151.75 really depends
Answer: Albert Einstein
Explanation:
Light can be considered as a wave or as particles, in this context Einstein proposed that light behaves like a stream of particles called <u>photons</u> with an energy, in order to correctly explain the photoelectric effect (in fact he won the 1921 Nobel Prize in Physics because of this explanation).
To uderstand it better:
The photoelectric effect is a fenomenom that consists in the emission of electrons that occurs when light falls on a metal surface under certain conditions.
This can only be explained based on the corpuscular model of light, that is, light is quantized.
So, Einstein theorized light as a stream of energy packets called photons, this energy is able to pull an electron out of the crystalline lattice of the metal and communicate, in addition, a kinetic energy.
Answer:
The answer is C. anti social
Explanation:
Hope that helps!
Answer:
Explanation:
Area of square loop = L²
Flux Φ = area x magnetic field
= L²B
Frequency = f
angular velocity ω = 2πf
a )
Let at time t = 0 , the magnetic field is making 90 degree with the face of the loop
flux through loop = L²B
After time t , coil will turn by angle ω t = 2πft
Flux through the loop = L²B cosω t
Φ (t) = L²B cosω t
= L²B cos2πft
b )
emf induced e
= - d/dt [Φ (t)]
= - d/dt [ L²B cosω t]
= L²B ω sinω t
= L²B 2πf sin2πft
c )
current = e / R
(L²B ω/ R ) sinω t
Power delivered
P(t) = VI ,
VOLT X CURRENT
= AB ω sinω t X ( AB ω/ R ) sinω t
= L⁴B² 4π²f²/R sin²2πft
e )
torque = MB sinω t
τ(t) = i(L²B ) sinω t
= (L²B ω/ R ) sinω t x (L²B ) sinω t
= (L²B )²ω/ R sin²ω t
= (L²B )² 2πf/ R sin²2πft
