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Anvisha [2.4K]
3 years ago
12

A project is located in an area with a demand-response program and on a site that has enough room for a wind-turbine to allow fo

r on-site renewable energy. If the project implements both of these strategies, which of the following will occur?
A. The project's energy costs will decrease B. The project's renewable energy production will decrease C. The project's energy demands will decrease D. the project minimum energy performance will decrease
Physics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

A. The project's energy costs will decrease

Explanation:

Since the project is located in an area with a demand-response program and on a site that has enough room for a wind-turbine to allow for on-site renewable energy.

Hence, the project's energy costs will decrease very well because it's implementing both of these strategies;

- Area with demand-response program.

- On-site renewable energy.

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A Carnot engine takes 3000 J from a reservoir at 600 K, does some work, and discards some heat to a reservoir at 300 K. What is
exis [7]

Answer: 50%

Explanation: efficiency=power input/power output ×100

Eff.=300/600 ×100

Eff=½×100

Eff=50%

6 0
3 years ago
Which objects would be considered to be in free fall?
SVEN [57.7K]

Answer:

Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.

Explanation:

8 0
2 years ago
Read 2 more answers
Determine the energy required to accelerate an electron between each of the following speeds. (a) 0.500c to 0.900c MeV (b) 0.900
Aleonysh [2.5K]

Answer:

The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

Explanation:

We know that,

Mass of electron m_{e}=9.11\times10^{-31}\ kg

Rest mass energy for electron = 0.511 Mev

(a). The energy required to accelerate an electron from 0.500c to 0.900c Mev

Using formula of rest,

E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}

E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.500c)^2}{c^2}}}

E=0.582\ Mev

(b). The energy required to accelerate an electron from 0.900c to 0.942c Mev

Using formula of rest,

E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}

E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.942c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}

E=0.350\ Mev

Hence, The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

4 0
3 years ago
Convert 90 oF to Celcius, (write your answer up to 1st decimal point)
Mice21 [21]

Answer:

The answer is 32.2

Explanation:

Hope this helps

5 0
2 years ago
Read 2 more answers
the diameter and the length of a thin wire, approximately 1m in length, are measured as accurately as possible. what are the bes
slamgirl [31]

Answer:

1.) Micrometres screw gauge

2.) Tape rule.

Explanation:

Given that the diameter and the length of a thin wire, approximately 1m in length, are measured as accurately as possible.

what are the best instruments to use ?

To measure the diameter of a thin wire, the best instrument to use is known as micrometres screw gauge.

And to measure the length of a thin wire up to 1 m, the measuring device can be tape rule or long metre rule.

5 0
3 years ago
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