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jeka94
3 years ago
7

An underwater scuba diver looks up toward the water's surface. She sees a buoy floating on the surface and notes its location. S

he then realizes that the buoy may actually be in a different location because she is looking at it from underwater. What is the wave property that best explains this phenomenon?
Physics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

Refraction

Explanation:

  • Whenever there is a change in media through which light travels there is change in the speed of light due to which there is bending of light when there is change in the medium.
  • When a ray of light passes from and optically denser medium to and optically rarer medium then it bends away from the normal to the interface and vice-versa.

As here the scuba driver is looking from an optically denser medium to an optically rarer medium the boy may appear nearer to the diver in position than is actually in the air.

Snell's law gives the relation between the angle of incidence and the angle of refraction as:

n=\frac{sin\ i}{sin\ r}

where

n = refractive index

i = angle of incidence

r = angle of refraction

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Please help me with this question​
vovangra [49]

Answer:

1. 12 V

2a. R₁ = 4 Ω

2b. V₁ = 4 V

3a. A = 1.5 A

3b. R₂ = 4 Ω

4. Diagram is not complete

Explanation:

1. Determination of V

Current (I) = 2 A

Resistor (R) = 6 Ω

Voltage (V) =?

V = IR

V = 2 × 6

V = 12 V

2. We'll begin by calculating the equivalent resistance. This can be obtained as follow:

Voltage (V) = 12 V

Current (I) = 1 A

Equivalent resistance (R) =?

V = IR

12 = 1 × R

R = 12 Ω

a. Determination of R₁

Equivalent resistance (R) = 12 Ω

Resistor 2 (R₂) = 8 Ω

Resistor 1 (R₁) =?

R = R₁ + R₂ (series arrangement)

12 = R₁ + 8

Collect like terms

12 – 8 =

4 = R₁

R₁ = 4 Ω

b. Determination of V₁

Current (I) = 1 A

Resistor 1 (R₁) = 4 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 1 × 4

V₁ = 4 V

3a. Determination of the current.

Since the connections are in series arrangement, the same current will flow through each resistor. Thus, the ammeter reading can be obtained as follow:

Resistor 1 (R₁) = 4 Ω

Voltage 1 (V₁) = 6 V

Current (I) =?

V₁ = IR₁

6 = 4 × I

Divide both side by 4

I = 6 / 4

I = 1.5 A

Thus, the ammeter (A) reading is 1.5 A

b. Determination of R₂

We'll begin by calculating the voltage cross R₂. This can be obtained as follow:

Total voltage (V) = 12 V

Voltage 1 (V₁) = 6 V

Voltage 2 (V₂) =?

V = V₁ + V₂ (series arrangement)

12 = 6 + V₂

Collect like terms

12 – 6 = V₂

6 = V₂

V₂ = 6 V

Finally, we shall determine R₂. This can be obtained as follow:

Voltage 2 (V₂) = 6 V

Current (I) = 1.5 A

Resistor 2 (R₂) =?

V₂ = IR₂

6 = 1.5 × R₂

Divide both side by 1.5

R₂ = 6 / 1.5

R₂ = 4 Ω

4. The diagram is not complete

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Answer:

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Answer:

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Explanation:

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1=7000/Area

1(Area)=7000

Area=7000 m^2

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