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xz_007 [3.2K]
2 years ago
6

Determine the resistance of 100m of copper cable whose cross-sectional area is 1.5mm2​

Engineering
1 answer:
Soloha48 [4]2 years ago
4 0

Explanation:

1140 miliohms.

resistance = resistivity×length /area

= 0.0000000171 ohms x 100 meters / 1.5 mm^2

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The lab technician you recently hired tells you the following: Boss, an undisturbed sample of saturated clayey soil was brought
harkovskaia [24]

Answer:

The water of the saturated clayed soil is 66.67 %.

Explanation:

Given;

mass of saturated clayed soil, M_s = 600 g

mass of dry soil sample, M_d = 200 g

mass of water content, M_w = M_s - M_d = 600 g - 200 g = 400 g

The water content is determined as;

M_w(\%)  = \frac{M_s - M_d}{M_s} *100\%\\\\M_w(\%)  = \frac{600-200}{600} *100 \% \\\\M_w(\%)  = 66.67 \%

Therefore, the water of the saturated clayed soil is 66.67 %.

6 0
3 years ago
Water evaporating from a pond does so as if it were diffusing across an air film 0.15 cm thick. The diffusion coefficient of wat
Elodia [21]

Answer:

1.25 cm/day

Explanation:

An air thickness , (l) = 0.15 cm

Air Temperature =

(T_a)=20^0C = (20+273)K\\(T_a)=293K

Mass Diffusion coefficient (D) = 0.25cm^2/sec

If the air pressure (P_a) = 0.5 P_{sat}

We are to determine how fast will the water (H_2O) level drop in a day.

From the property of air  at T = 20° C

P_{sat} = 2.34 from saturated water properties.

The mass flow of (H_2O)  can be calculated as:

H_2O = \frac{D}{\phi} \delta C

where:

\delta C = \frac{P_{sat}*P_a}{RT }

R(constant) = 8.314 kJ/mol.K

\delta C = \frac{2.34*0.5}{8.314*293 }

\delta C = 4.803*10^{-4}\\ \delta C =0.48*10^{-3} mol/m^3\\ \delta C = 0.48*10^{-6} mol/cm^3

Since 1 mole = 18 cm ³ of water

0.48*10^{-6}mol/cm^3 will be: (0.48*10^{-6}mol/cm^3 *18)cm^3/cm^3

\delta C = 8.64 * 10^{-6}

Again:

H_2O = \frac{D}{\phi} \delta C

= \frac{0.25}{0.15}*8.69*10^{-6} \frac{cm^2/sec}{cm}

=1.4481*10^{-5} \frac{cm^2/sec}{cm}

Converting the above value to cm/day: we have:

1.448*10^{-5}*3600*24\frac{cm}{s}*\frac{s}{yr}*\frac{yr}{day}

= 1.25 cm/day

∴ the rate at which  the water level drop in a day = 1.25 cm/day

7 0
3 years ago
It is important to follow correct procedures when running electrical cables next to data cables in order to protect against whic
zloy xaker [14]

Answer:

Temperature, humidity, and airflow are all important parts of environmental control, but they do not interfere with data cabling. ...

Explanation:

Hope its help you

5 0
2 years ago
The input power for a thermostat is wired to the
masya89 [10]

Answer:

A. R

Explanation:

There are basically two wires that supply input power to the thermostat namely the C wire which is the common wire and the R wire .The G wire simply completes the input power circuit from the R-leg of the power supply.On the another hand the Y wire also completes the circuit  from the compressor fan contactor to the R-leg of the power supply . While the W wire completes the path to the heater contactor coil.

6 0
3 years ago
Most technician jobs in the field of metrology require a college degree. True or False?
Elanso [62]

Answer:

True

Explanation:

Because I Said

7 0
3 years ago
Read 2 more answers
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