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3 years ago

What could be used as another word for electrical potential?

Engineering

1 answer:

Marat540 [252]3 years ago

6 0

Answer: C. Voltage

Explanation:

Here are some other words as well.

potential, voltage, potential drop, potential difference.

Answered by the ONE & ONLY #QUEEN aka #DRIPPQUEENMO!!!

HOPE THIS HELPED!!!

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20. What is a "whipping motion and why is it<br> used?

Reptile [31]

Whipping is done in a forward direction. You deposit a dab or puddle of metal down, and then whip the rod forward and up a little to let that dab cool a bit, then you move back and deposit another dab slightly ahead of the previous dab.
Cellulose rod like 6010 and 6011 are known as "fast freeze" electrodes, also known to be deep penetrating rods. The "whip and stitch" motion is used so that you get the full benefit of the cellulose characteristics. The forward motion basically gouges out the base metal, and it gets filled in with the back-step.
Hope this helped:)

6 0

4 years ago

Consider the simplicity of these two DOE examples. Next, consider the assertion that DOE isn’t put into practice as often or dee

Bingel [31]

Answer:

Do Re Mi

Explanation:

I have no clue sorry

5 0

3 years ago

Technician A says that a 12 Volt light bulb that draws 12 amps has a power output of 1 watt. Technician B says that a motor that

Artemon [7]

Answer:

Technician B

Explanation:

Resistance, $R=\frac {V}{I}$ where V is the voltage and I is the current in amps

Therefore, $R=\frac {12}{12}=1 ohm$

Power=VI=12*12=144 W

Therefore, the power is 144 W and resistance is 1 Ohm. This implies that technician A is wrong while technician B is correct

6 0

4 years ago

Consider a turbojet powered airplane flying at a standard altitude of 30,000ft at a velocity of 500 mph. The turbojet engine its

grandymaker [24]

Answer:

T = 20.42 N

Explanation:

given data

standard altitude = 30,000 ft

velocity Ca = 500 mph = 0.4 m/s

inlet areas Aa = 7 ft² = 0.65 m²

exit areas Aj = 4.5 ft² = 0.42 m²

velocity at exit Cj = 1600 ft/s = 487.68 m/s

pressure exit $\rho$ j = 640 lb/ft² = 0.3 bar

solution

we get here thrust of the turbojet that is express as

thrust of the turbojet T = Mg × Cj - Ma × Ca + ( $\rho$ j Aj - $\rho$ a Ag ) .............1

here Ma = Mg

Ma = $\rho$ a × Ca Aa = 0.042 kg/s

put value in equation 1 we get

T = 0.042 × (487.68 -0.14) + ( 0.3 × - 0.3 × 0.65 )

T = 20.42 N

5 0

3 years ago

Beverage in cans 150 mm long and 60 mm in diameter is initially at 27°C and is to be cooled by placing it in a refrigerator comp

JulijaS [17]

Answer:

See attached pictures.

Explanation:

See attached pictures.

5 0

4 years ago