2 years ago

Radioactive elements include all those elements whose nuclei contain more than

Chemistry

1 answer:

andrey2020 [161]2 years ago

6 0

Bbgfbsthgbdvdge fr that’s crazy d. Thx

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At room temperature, a melting solid produces a whitish liquid. A laser beam shined through the liquid is unaffected and produce

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Balance the following and label what type of reaction is taking place:

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How do you draw acetone using a Bohr model?

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When the equation below is balanced, the coefficient of sulfuric acid, h2so4 is: nacn + h2so4 → na2so4 + hcn?

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3 years ago

Consider two concentric spheres whose radii differ by t = 1 nm, the "thickness" of the interface. At what radius (in nm) of sphe

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Answer:

Radius of the interior sphere = 3.847 nm

Explanation:

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$V_s=V_o-V_i=V_i\\V_o=2*V_i\\$

If we express the radius of the outer sphere (ro) in function of the radius of the inner sphere (ri), we have (e being the shell thickness):

$r_o=r_i+e$

The first equation becomes

$\frac{4 \pi}{3}*r_o^{3} = 2 * \frac{4 \pi}{3}*r_i^{3} \\\\\frac{4 \pi}{3}*(r_i+e)^{3} = 2 * \frac{4 \pi}{3}*r_i^{3} \\\\(r_i+e)^{3} = 2 *r_i^{3} \\\\(r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3})=2r_i^{3}\\\\-r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3}=0\\\\-r_i^{3}+3r_i^{2}+3r_i+1=0$

To find ri that satisfies this equation we have to find the roots of the polynomial.

Numerically, it could be calculated that ri=3.847 nm satisfies the equation.

So if the radius of the interior sphere is 3.847 nm, the volume of the interior sphere is equal to the volume of the shell of 1nm.

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2 years ago