<span>A "White" colored light must be shown by a 14-foot boat that is operating under oars after it is dark, in order to prevent a collision.
Boats which are less than 23 feet cannot exceed a maximum speed of 7 knots. They need to exhibit an all-around white light when it is sailing in the dark.
The other practicable sidelights can also be used instead of the white lights, when they are sailing in international waters.
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Answer:
It would take the object 5.4 s to reach the ground.
Explanation:
Hi there!
The equation of the height of a free-falling object at any given time, neglecting air resistance, is the following:
h = h0 + v0 · t + 1/2 · g · t²
Where:
h = height of the object at time t.
h0 = initial height.
v0 = initial velocity.
g = acceleration due to gravity (-32.2 ft/s² considering the upward direction as positive).
t = time
Let´s supose that the object is dropped and not thrown so that v0 = 0. Then:
h = h0 + 1/2 · g · t²
We have to find the time at which h = 0:
0 = 470 ft - 1/2 · 32.2 ft/s² · t²
Solving for t:
-470 ft = -16.1 ft/s² · t²
-470 ft / -16.1 ft/s² = t²
t = 5.4 s
Answer: The Company has spent $5 million in research and development over the past 12 months developing cutting-edge battery technology which will be incorporated ...
Explanation: uhmmmmmm i dont know this one but it is pretty ez
The angle measured counterclockwise from the positive x-axis is θ = 50.4°
<h3>
How to get the angle correspondent to a vector?</h3>
Here we know that the vector is:
V = < -177 cm, -214 cm>
To get the correspondent angle for this vector, we can think that this is the hypotenuse of a right triangle, such that the y-component and x-component are the cathetus.
Then, to get the angle (measured counterclockwise from the positive x-axis) is given by:
Tan(θ) = (opposite cathetus)/(adjacent cathetus)
Tan(θ) = (-214cm)/(-177 cm)
Using the inverse tangent function we get:
Atan(Tan(θ)) = Atan((-214cm)/(-177 cm))
θ = 50.4°
So the angle is 50.4°
If you want to learn more about vectors, you can read:
brainly.com/question/3184914