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alex41 [277]
3 years ago
12

Kaylah's cell phone has a mass of 50,000 centigrams. what is the mass of her phone in grams

Mathematics
1 answer:
Mashutka [201]3 years ago
7 0
50,000 centigrams / 100 = 500 grams

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The distance d (in feet) that it
Marta_Voda [28]

Answer:

40 mph

Step-by-step explanation:

To find the maximum speed at which the car can travel, as the distance it requires to stop is 168 feet, we just need to use the value of d = 168 in the equation, and then find the value of s:

168 = 0.05s^2 + 2.2s

0.05s^2 + 2.2s - 168 = 0

Using Bhaskara's formula: we have:

Delta = 2.2^2 + 4*0.05*168 = 38.44

sqrt(Delta) = 6.2

s1 = (-2.2 + 6.2)/0.1 = 40 mph

s2 = (-2.2 - 6.2)/0.1 = -84 mph (a negative value does not make sense as 's' is the speed of the car)

So the maximum speed of the car is 40 mph

3 0
3 years ago
If the price of a cd that normally costs $17.50 was marked up by 8% what is the new cost
Nana76 [90]
CD cost=17.50
Marked up=8%
So 8%of 17.50
8÷100×17.50=1.4
So add the old cd cost to the answer
=17.50+1.4=18.9 is the new cost
3 0
3 years ago
I need urgent help with this. please write out the working and the answer thank you
Lelechka [254]
1.         C = ⁵/₉F - 32
          9C = 9(⁵/₉F - 32)
          9C = 9(⁵/₉F) - 9(32)
          9C = 5F - 288
        - 5F  - 5F
  9C - 5F = -288
- 9C           - 9C
         -5F = -9C - 288
          -5           -5
            F = 1⁴/₅C + 57.6

2. H = w + \frac{50}{m^{2}}
    m^{2}(H) = m^{2}(\frac{50}{m^{2}})
    Hm^{2} = 50
    \frac{Hm^{2}}{H} = \frac{50}{H}
    m^{2} = \frac{50}{H}
    \sqrt{m^{2}} = \sqrt{\frac{50}{H}}
    m = \frac{\sqrt{50}}{\sqrt{H}}
    m = \frac{5\sqrt{2}}{\sqrt{H}}
    m = \frac{5\sqrt{2}}{\sqrt{H}} * \frac{\sqrt{H}}{\sqrt{H}}
    m = \frac{5\sqrt{2H}}{H}

3.                    A = 5 + 4√x
                     - 5  - 5
                  A - 5 = 4√x
              (A - 5)² = (4√x)²
    A² - 10A + 25 = 16x
             16             16
¹/₆A² - ⁵/₈A + 1⁹/₁₆ = x

4. A = \frac{b + c}{b}
    Ab = b(\frac{b + c}{b})
    Ab = b + c
    Ab - b = c
    b(A) - b(1) = c
    b(A - 1) = c
    \frac{b(A - 1)}{A - 1} = \frac{c}{A - 1}
    b = \frac{c}{A - 1}
3 0
3 years ago
Tan2°- cot 88° evaluate​
nika2105 [10]

Answer:

0

Step-by-step explanation:

tan2°- cot 88° = tan 2° - tan (90-88)°

= tan 2°-tan 2° = 0

5 0
3 years ago
Read 2 more answers
BD and AC are chords that intersect at point Y. What is the length of line segment AY? 2 units 3 units 4 units 6 units
Anna71 [15]

Answer:

4 units

Step-by-step explanation:

The complete question is

BD and AC are chords that intersect at point Y. A circle is shown. Chords B D and A C intersect at point Y. The length of B Y is 3, the length of Y D is 8, the length of A Y is x, and the length of Y C is 6. What is the length of line segment AY?

The picture of the question in the attached figure

we know that

The Intersecting Chord Theorem states that:  When two chords intersect each other inside a circle,the products of their segments are equal.

do

In this problem

substitute the given values

solve for x

therefore

The length of segment AY is 4 units

5 0
4 years ago
Read 2 more answers
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