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Dovator [93]
3 years ago
13

You find that 7.36g of a compound has decomposed to give 6.93g of oxygen. The only other element is hydrogen. If the molar mass

of the compound is 34.0g/mol, what is its molecular formula?
Chemistry
1 answer:
OleMash [197]3 years ago
6 0

Answer:

The molecular formula of this compound is H_{2}O_{2}

Explanation:

From the given,

Mass of compound = 7.36 g

Molar mass of compound = 34.0 g/mol

The mass of oxygen = 6.93 g

The hydrocarbon contains only hydrogen and carbon.

Mass of hydrogen + Mass of oxygen = 7.36 g

Mass of hydrogen + 6.93 g = 7.36 g

Mass of hydrogen = 7.36 - 6.93 = 0.43g

Molar mass of hydrogen = 1.0 g/mol

Molar mass of oxygen = 16 g/mol

Number\,of\,moles\,of \,Oxygen=6.93g\times\frac{1}{16}=0.43mol

Number\,of\,moles\,of \,hydrogen=0.43g\times\frac{1}{1}=0.43mol

Now divided each one by 0.43

Oxygen:

\frac{0.43}{0.43}=1

Hydrogen :

\frac{0.43}{0.43}=1

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ch4aika [34]

Answer:

the answer to this question is  2 kilogram/cubic meter

Explanation:

4 0
3 years ago
What is the net ionic equation for the reaction if any that occurs when aqueous solutions of Na2CO3 and HCL are mixed?
strojnjashka [21]

Answer:

CO₃²⁻(aq)  +  2H⁺(aq) → CO₂ (g)  + H₂O (l)

Explanation:

The balanced reaction between Na2CO3 and HCl is given as;

Na₂CO₃ (aq) + 2 HCl (aq) → 2 NaCl (aq) + CO₂ (g) + H₂O (l)

The next step is o express the species as ions.

The complete ionic equation for the above  reaction would be;

2Na⁺(aq)  + CO₃²⁻(aq)  +  2H⁺(aq)  + 2Cl⁻(aq)   → Na⁺(aq)  + Cl⁻(aq)  + CO₂ (g)  + H₂O (l)

The next step is to cancel out the spectator ion ions; that is the ions that appear in both the reactant and product side unchanged.

The spectator ions are;  Na⁺ and Cl⁻

The net ionic equation is given as;

CO₃²⁻(aq)  +  2H⁺(aq) → CO₂ (g)  + H₂O (l)

7 0
2 years ago
How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 4.46 atm and 45°C in the reaction shown below?
natka813 [3]

Answer:

8.1433 g of XeF₆  are required.

Explanation:

Balanced chemical equation;

XeF₆ (s) + 3H₂ (g)   →  Xe (g) + 6HF (g)

Given data:

Volume of hydrogen = 0.579 L

Pressure = 4.46 atm

Temperature = 45 °C (45+273= 318 k)

Solution:

First of all we will calculate the moles of hydrogen

PV = nRT

n = PV/ RT

n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K

n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹

n = 0.0995 mol

Mass of hydrogen:

Mass = moles × molar mass

Mass =  0.0995 mol × 2.016 g/mol

Mass =  0.2006 g

Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.

                                         H₂   :  XeF₆

                                          3    :    1

                                 0.0995   : 1/3× 0.0995 = 0.0332 mol

Now we will calculate the mass of XeF₆.

Mass = moles × molar mass

Mass = 0.0332 mol × 245.28 g/mol

Mass = 8.1433 g

4 0
3 years ago
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REY [17]

Answer:

Heating the mixture to a temperature above the boiling point of acetic acid, but below 100°C (the boiling point of water). The vapours from the acetic acid rise, and go into a tube. They are then condensed within the tube, and run off into a separate storage area. Because water can exist as a gas at pretty much any temperature above 0°C, it will result in an impure mixture, but repeatedly doing this will get the acetic acid to the desired purity.

8 0
3 years ago
What is the part of an experiment that is not being tested and is used for comparison
STALIN [3.7K]
The controlled variable, I think.
7 0
3 years ago
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