The percent yield of this reaction is calculated as follows
Mg3N2 + 3H2O =2NH3 + 3Mgo
calculate the theoretical yield,
moles=mass/molar mass
moles Mg3N2= 3.82 g/100g/mol= 0.0382 moles(limiting regent)
moles of H2o= 7.73g/18g/mol = 0.429 moles ( in excess_)
by use of mole ratio between Mg3N2 to MgO which is 1:3 the moles of MgO = 0.0382 x3 = 0.1146 moles
mass =moles x molar mass
the theoretical mass is therefore = 0.1146mole x 40 g/mol = 4.58 grams
The % yield = actual mass/theoretical mass x1000
= 3.60/4.584 x100= 78.5%
Reaction is NaHCO3 + HCL = H2CO3 + NaCl
the ratios are 1:1
the 8 moles of HCl are in excess
so if you use 4 moles of NaHCO3 then you will obtain 4 moles of carbonic acid
hope that helps
The pressure of the atmosphere Boiling point is defined as when the vapor pressure of the liquid equals to the atmospheric pressure then it starts to boil that temperature is called boiling point.
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Option C= ions are exchanged between two compounds.
<h3>Explanation
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A double displacement reaction, also known as a double replacement reaction or metathesis, is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products. For example,
Na2S + 2HCl → H2S + 2NaCl
Option D is incorrect because electrons are exchanged between the atoms in oxidation –reduction reactions.
Answer: The density of the unknown metal is 7.86 g/ml.
Explanation:
Density is defined as the mass contained per unit volume.
Given : Mass of metal = 25.32 g
Volume of metal = volume of water displaced = (28.22 - 25.00) ml = 3.22 ml
Putting in the values we get:
Thus the density of the unknown metal is 7.86 g/ml