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Sergio039 [100]
3 years ago
8

The accommodation limits for a nearsighted person's eyes are 20.0 cm and 82.0 cm. When he wears his glasses, he can see faraway

objects clearly. At what minimum distance is he able to see objects clearly

Physics
1 answer:
Alchen [17]3 years ago
6 0

Answer;

26.45cm

See attached file for explanation

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The magnitude of a velocity vector is called speed. Suppose that a wind is blowing from the direction N45°W at a speed of 50 km/
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w⃗ +P⃗ ,

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ground speed=||w⃗ +P⃗ ||

 

Using the planar representation of your situation, this will help you understand the equation, use this to make the equation more understandable.

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w⃗ =⟨50cos(135),50sin(135)⟩=⟨−252√, 252√⟩.

P⃗ =⟨200cos(60),200sin(60)⟩=⟨100,\1003√⟩.

w⃗ +P⃗ =⟨100−252√ , 1003√+252√⟩

||w⃗ +P⃗ ||=(100−252√)2+(1003√+252√)2

√≈218.349218.

 

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Which of the following is a category of mechanical wave?
givi [52]

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a

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<span>So the nurse must exert 80.34 N of force</span>

4 0
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