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Goshia [24]
3 years ago
13

In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac

eship is approximately 274 m long but part of it is packed with gunpowder, so it accelerates over a distance of only 213 m. What was the acceleration (in m/s2) experienced by the occupants of the spaceship during the launch?
Physics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

a=0.284\ m/s^2

Explanation:

Given that,

Initially, the spaceship was at rest, u = 0

Final velocity of the spaceship, v = 11 m/s

Distance accelerated by the spaceship, d = 213 m

We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2

So, the acceleration experienced by the occupants of the spaceship is 0.284\ m/s^2.

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Answer:

Let's start by explaining that each atom in its natural state has a specific structure of its energy levels. Where the lowest energy level is called the ground state.

At this level, as long as no energy is communicated to the atom, the electron will remain in the ground state.

What does this mean?

When an atom is in its ground state, its electrons fill the lower energy orbitals completely before they begin to occupy higher energy orbitals.

3 0
3 years ago
A beam of light has a wavelength of 620 nm in vacuum.
crimeas [40]

Explanation:

It is given that,

Wavelength of a beam of light in vacuum, \lambda_o=620\ nm

(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.

We know that,

Refractive index,

n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s

(b) The wavelength of light in material,

\lambda=\dfrac{\lambda_o}{n}

Let \lambda_1 is the wavelength of these waves in the liquid. So,

\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m

Hence, this is the required solution.

7 0
4 years ago
For the long life cells we have to connect them in ____ combination​
NISA [10]

Answer:

Parallel combination.

5 0
3 years ago
Read 2 more answers
Help please help me with all of it I don't know nothing. bless ur hearts <br>​
Evgesh-ka [11]

Answer:

200 , 0 , 133.33333

Explanation:

velocity = change of X / change of T

so

400/2 = 200

0/2 = 0

400/3 = 133.33333

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The sun is 1.50x10^11 m from earth. How long does it take the suns light to reach earth? How long
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