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Goshia [24]
3 years ago
13

In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac

eship is approximately 274 m long but part of it is packed with gunpowder, so it accelerates over a distance of only 213 m. What was the acceleration (in m/s2) experienced by the occupants of the spaceship during the launch?
Physics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

a=0.284\ m/s^2

Explanation:

Given that,

Initially, the spaceship was at rest, u = 0

Final velocity of the spaceship, v = 11 m/s

Distance accelerated by the spaceship, d = 213 m

We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2

So, the acceleration experienced by the occupants of the spaceship is 0.284\ m/s^2.

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A laser beam enters a 12.0 cm thick glass window at an angle of 33.0° from the normal. The index of refraction of the glass is 1
Alenkinab [10]

Answer:

The time is 0.563 ns.

Explanation:

Given that,

Index of refraction of glass = 1.41

Distance = 12.0 cm

Angle = 33.0°

We need to calculate the refraction angle

Using Snell's law

n_{1}\sin\theta=n_{r}\sin\theta

put the value into the formula

1\times\sin33=1.41\sin\theta

\sin\theta=\dfrac{1\times\sin33}{1.41}

\theta=22.71^{\circ}

We need to calculate the velocity of beam in glass

Using formula of velocity

v=\dfrac{c}{n}

Put the value into the formula

v=\dfrac{3\times10^{8}}{1.41}

v=2.13\times10^{8}\ m/s

We need to calculate the time

Using formula of distance

v=\dfrac{d}{t}

t=\dfrac{12.0\times10^{-2}}{2.13\times10^{8}}

t=5.63\times10^{-10}\ sec

t=0.563\times10^{-9}\ sec

t=0.563\ ns

Hence, The time is 0.563 ns.

6 0
3 years ago
Anaya Goodloe decides to spike the football after a big touchdown (on Earth) and it
Llana [10]

Answer:

The football leaves with the velocity, u = 15.68 m/s

Explanation:

Given data,

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Let the football bounces back up off the ground in the vertical direction

The formula for time of flight is given by,

                              t = 2u /g

∴                             u = gt / 2

Substituting the values,

                               u = 9.8 x 3.2 / 2

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Hence, the football leaves with the velocity, u = 15.68 m/s

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Explanation:

kinetic to gravitational

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3 years ago
you are building a race car. Your goal is to have a car that can go from 0 miles per hour to 80 miles per hour in 2 seconds. You
Vitek1552 [10]
<span>You want to focus on the car's acceleration.
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6 0
3 years ago
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Answer:

no

Explanation:

they cannot because they contain the same amount of liquid

8 0
3 years ago
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