Answer:
-639288.89 N/C
Explanation:
x = 21-6 = 13.5 cm
= 6 cm
= 21 cm
k = Coulomb constant =
The net electric field is given by
The net electric field is
Answer:
(a). = 5.43
(b). 13
(C) 0
Explanation:
part A:
φ(outside) = ∬B(outside) dS
note that;
φ(sum) = 2[φ(outside) + φ(inside).
then, we say
φ(outside) = ∫ μI/ 2πr dr (taking boundaries at R - d/2 and d/2.
μI/2πr dr= μI/2πr ln 2R- d/d
= 1.26× 1) ^-6 ×10 ln 40-2.5/2.5.
= 5.43 μWb.
magnetic flux in the conductor can be calculated from magnetic induction as integral of d/2 to R
please note that dS= 1. dr
φ (inside) = B(inside) dS
∫2μIr/ π d^2 dV.
μI/πd2 r^2 (at boundary d/2 and 0)
μI/4π
= 1.26×10^-6 ×10/4π.
= 1.0032 μWb .
where B(inside) = μI(inside)/ 2πr and I= Ir^2/ (d/2) ^2.
φ(sum)= φ(outside + inside)
=2(5.42 + 1.0032
= 13μWb
(c). is zero
Answer:
Workdone = 2906.25J
Explanation:
Given the following data;
Force, F = 155
Distance, d = 0.75
Stroke, s = 25
Mathematically, work done is given by the formula;
Work done = force * distance * stroke
Where,
W is the work done
F represents the force acting on a body.
d represents the distance covered by the body.
s is the number of strokes.
Substituting into the equation, we have;
Workdone = 2906.25J
Answer:
C. identity of the element
The specific amount of energy emitted when electrons jump from excited states to the ground state refers to emission spectrum. The energy is emitted in the form of photons, and the photons have very specific wavelengths (energy) that correspond to the energy gaps between the excited states and the ground state. The specific wavelengths of light emitted are referred to as the "emission spectrum," and each element produces a different emission spectrum. Thus, this emitted energy can be used to identify the element from which your sample was taken.
Explanation: