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expeople1 [14]
2 years ago
8

I will give Brainliest please help!​

Physics
1 answer:
mote1985 [20]2 years ago
3 0

Answer:

A) Golgi apparatus

Explanation:

B) v a c u o l e (C) m i t o c h o n d r i a ( E) cell wall

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Hey guys. What is physically?<br><br> Help me to find a moderator!!!! Please.
aivan3 [116]

Answer:

Physical indicates connected with, pertaining to, the animal or human body as a material organism: physical strength, exercise. Bodily means belonging to, concerned with, the human body as distinct from the mind or spirit: bodily pain or suffering.

3 0
2 years ago
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The work done when a force moves a body through a distance of 15m is 1800j. What is the value of the force applied
Leviafan [203]

Answer:

120

Work :

W = Fd (work = force x distance)

Force :

F = W/d

Distance :

d = W/F

7 0
3 years ago
Examine the spectra of the four unknown substances shown below. What can you conclude?
oksian1 [2.3K]
Line spectra are obtained when individual elements are heated using a high-voltage electrical discharge. This heating causes excitation of the element and a subsequent emission of distinct lines of colored light are obtained. Each element has its own unique emission line spectrum; therefore, if any of the tested substances were the same, their spectra would match. However, this is not the case so none of the substances are the same.
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7 0
3 years ago
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The central star of a planetary nebula emits ultraviolet light with wavelength 104nm. This light passes through a diffraction gr
Gala2k [10]

Answer: 31.33 degrees

Explanation:

The diffraction angles \theta_{n} when we have a slit divided into n parts are obtained by  the following equation:

dsin\theta_{n}=n\lambda   (1)

Where:

d is the width of the slit

\lambda  is the wavelength of the light

n is an integer different from zero.

Now, the first-order diffraction angle is given when n=1, hence equation (1) becomes:

dsin\theta_{1}=\lambda   (2)

Now we have to find the value of \theta_{1}:

sin\theta_{1}=\frac{\lambda}{d}  

\theta_{1}=arcsin(\frac{\lambda}{d})   (3)

We know:

\lambda=104nm=104(10)^{-9}m

In addition we are told the diffraction grating has 5000 slits per mm, this means:

d=\frac{1mm}{5000}=\frac{1(10)^{-3}m}{5000}

Substituting the known values in (3):

\theta_{1}=arcsin(\frac{104(10)^{-9}m}{\frac{1(10)^{-3}m}{5000}})

\theta_{1}=arcsin(0.52)

<u>Finally:</u>

\theta_{1}=31.33\º >>>This is the first-order diffraction angle

4 0
2 years ago
The standard wave format for any wave is
Novay_Z [31]
The standard wave format for any wave is transverse wave
8 0
3 years ago
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