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padilas [110]
3 years ago
6

How does increasing the tension of a spring affect a wave on the spring?

Physics
2 answers:
Alla [95]3 years ago
4 0
Increasing the tension of a spring affects a wave on the spring because it increases the frequency. When the tension rises, so does the frequency.
mezya [45]3 years ago
3 0

Answer: Increases the frequency of the wave

Explanation:

Increasing the tension of a spring means increasing its stiffness. The wave produced thereafter has greater frequency.  

Higher tension causes the spring to have greater restoring force causing it to quickly come back to its equilibrium position. Thus, the speed of the wave also increases.

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a. applied science

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3 years ago
Suppose the glass paperweight has index of refraction n=1.38. a) find the value of θ for which the reflection on the vertical su
zimovet [89]

Answer:

a)θ=71.89°

b)NO

Explanation:

Given that

For glass n= 1.38

We know that for air n'=1

The angle  for total internal reflection θc given as

sin θc=n'/n

By putting the values

sin θc=n'/n

sin θc=1/1.38

θc=46.43°

n'sinθ = n sinθref

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1 x sinθ =1.38 x cos 46.43°

θ=71.89°

b)

NO

8 0
4 years ago
The capacitor is now disconnected from the battery, and the plates of the capacitor are then slowly pulled apart until the separ
alexdok [17]

Answer:

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

Explanation:

The energy stored in a capacitor is given by (1/2) (CV²)

Energy in the capacitor initially

U = CV²/2

V = voltage across the plates of the capacitor

C = capacitance of the capacitor

But the capacitance of a capacitor depends on the geometry of the capacitor is given by

C = ϵA/d

ϵ = Absolute permissivity of the dielectric material

A = Cross sectional Area of the capacitor

d = separation between the capacitor

So,

U = CV²/2

Substituting for C

U = ϵAV²/2d

Now, for U₁, the new distance between plates, d₁ = 3d

U₁ = ϵAV²/2d₁

U₁ = ϵAV²/(2(3d))

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

3 0
3 years ago
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