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padilas [110]
3 years ago
6

How does increasing the tension of a spring affect a wave on the spring?

Physics
2 answers:
Alla [95]3 years ago
4 0
Increasing the tension of a spring affects a wave on the spring because it increases the frequency. When the tension rises, so does the frequency.
mezya [45]3 years ago
3 0

Answer: Increases the frequency of the wave

Explanation:

Increasing the tension of a spring means increasing its stiffness. The wave produced thereafter has greater frequency.  

Higher tension causes the spring to have greater restoring force causing it to quickly come back to its equilibrium position. Thus, the speed of the wave also increases.

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Please help me! Uniform acceleration problem sheet:
Brrunno [24]

From the calculation, the value of the acceleration is 5.8 m/s^2.

<h3>What is uniform acceleration?</h3>

The term uniform acceleration refers to a situation in which the velocity increases by equal amounts in equal time intervals.

Given the fact that the car started from rest and reached a velocity of  780.34 mph or 348.84 m/s in 1 minute of 60 seconds;

v = u + at

a = v/t

a = 348.84 m/s/ 60 seconds

a = 5.8 m/s^2

Learn more about acceleration:brainly.com/question/12550364?

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7 0
2 years ago
A weightlifter lifts a 1,250 N barbell 2 m in 3 s. How much power was used to lift the barbell?
OverLord2011 [107]
brainly.com/question/1478685 
5 0
3 years ago
When energy is added to a wave, how can the wave change?.
nadya68 [22]

Answer:

When waves overlap in-phase (crest meets crest or trough meets trough) the waves energy is additive and the amplitude increases.

Explanation:

When waves overlap out-of-phase (crest meets trough) the waves cancel and the amplitude (energy) decreases. When two interfering waves cancel each other out.

6 0
2 years ago
A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in
Kryger [21]

The average power is 3.0\cdot 10^6 W

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where :

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the car, with

m = 2000 kg is the mass of the car

v = 60 m/s is the final speed of the car

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the car, with

u = 30 m/s is initial speed of the car

Soolving:

W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J

Now we can find the power required for the acceleration, which is given by

P=\frac{W}{t}

where

t = 9 s is the time elapsed

Solving:

P=\frac{2.7\cdot 10^6}{9}=3.0\cdot 10^6 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

8 0
3 years ago
Usa test prep- Look at the picture below to answer. If u answer correctly i will mark you as brainliest!
Vladimir [108]

Answer:

A

Explanation:

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Hopefully this helps...

4 0
3 years ago
Read 2 more answers
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