Answer:
Explanation:
mass of sled, m = 22 kg
Force of pull, F = 31 N
distance move, d = 53 m
Angle between force and distance, θ = 40°
The formula for the work done is
W = F x d x Cos θ
W = 31 x 53 x cos 40
W = 1258.6 J
Answer:
Grow up man, this is completely based on your curriculum, we would need your book to answer, and this has to be done by you.
Answer:
The magnification of an astronomical telescope is -30.83.
Explanation:
The expression for the magnification of an astronomical telescope is as follows;

Here, M is the magnification of an astronomical telescope,
is the focal length of the eyepiece lens and
is the focal length of the objective lens.
It is given in the problem that an astronomical telescope having a focal length of objective lens 74 cm and whose eyepiece has a focal length of 2.4 cm.
Put
and
in the above expression.

M=-30.83
Therefore, the magnification of an astronomical telescope is -30.83.
Answer:
50 N.
Explanation:
On top of a horizontal surface, the normal force acting on an object is equivalent to the force of gravity acting on the object. That is:

The mass of the block is 5 kg and the given force due to gravity is 10 N/kg. Substitute and evaluate:

In conclusion, the normal force acting on the block is 50 N.