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liubo4ka [24]
3 years ago
14

A 1.2-kg object moving with a speed of 8.0 m/s collidesperpendicularly with a wall and emerges with a speed of 6.0 m/s inthe opp

osite direction. If the object is in contact with the wallfor 2.0 ms, what is the magnitude of the average force on theobject by the wall?
a. 9.8 kNb. 8.4 kNc. 7.7 kNd. 9.1 kNe. 1.2 kN
Physics
1 answer:
steposvetlana [31]3 years ago
3 0

Answer:

8.4 kN

Explanation:

Change in momentum = m₁v₁- m₂v₂ = m(v₁-v₂) = 1.2[8 - (-6)] = 16.8kgm/s

v₂ has been taken as negative because velocity of object colliding ball as +ve. Both are in opposite directions.

Change in momentum = impulse = Force × Time

Time = 2 ms = 2 milli seconds = 0.002 s.

Force = Change in momentum/Time = 16.8/0.002 = 8.4kN

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