Costal residents must do many things to prepare for hurricanes
1 answer:
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Answer:
The resistance that will provide this potential drop is 388.89 ohms.
Explanation:
Given;
Voltage source, E = 12 V
Voltage rating of the lamp, V = 5 V
Current through the lamp, I = 18 mA
Extra voltage or potential drop, IR = E- V
IR = 12 V - 5 V = 7 V
The resistance that will provide this potential drop (7 V) is calculated as follows:
IR = V
Therefore, the resistance that will provide this potential drop is 388.89 ohms.
Answer:
2d
Explanation:
For any instance equivalent force acting on the body is
Where
m is the mass of the object
k is the force constant of the spring
d is the extension in the spring
and
d/dt(dx/dt)= is the acceleration of the object
solving the above equation we get
where
A is the amplitude of oscillation from the mean position.
k= spring constant , T= time period
Here we are assuming that at t=T/4
x= 0 since, no extension in the spring
then
A=- d
Hence
x=- d sin wt + d
now, x is maximum when sin wt=- 1
Therefore,
x(maximum)=2d