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Vlad [161]
2 years ago
6

Why is water important?​

Chemistry
1 answer:
expeople1 [14]2 years ago
4 0

Answer:

Its a natural resource used around the world

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A new planet is discovered in a different solar system. The new planet is much like Earth. One difference is that the planet doe
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Using a value of Ksp = 1.8 x 10-2 for the reaction PbCl2 Pb+2(aq) + 2Cl -(aq). If the value of Ksp was determined to be only 1.2
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Answer:

The correct answer is option D, that is, the ions are now combining to reduce their concentrations.

Explanation:

On the basis of the chemical equation:  

PbCl₂ (s) ⇒ Pb²⁺ (aq) + 2Cl⁻ (aq)

It is mentioned that the value of Ksp is 1.8 × 10⁻²

As the solubility product is very less or negligible for this reaction that signifies that the ions produced are getting combined, resulting in the reduction of the concentration of the ions and enhancing the formation of the solid lead chloride. Therefore, they associate together to produce solid lead chloride.  

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Hydrogen gas explosive within range of 4%-75% v/v. Assuming that each student in your class produces 6 L of H2 and that the lab
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How many Groups is the modern periodic table divided into?<br> A. 2<br> B. 3<br> C. 7<br> D. 18
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A 10.0cm3 volume of alcohol has a mass of 7.05g. What the density
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A 10.0cm3 volume of alcohol has a mass of 7.05g. 0.705 \frac{g}{c m^{3}} is the density

Answer:  0.705 \frac{g}{c m^{3}}

<u>Explanation:</u>

The ratio between the mass of a substance and its unit volume is referred as density.

\text {Density}=\frac{\text { mass }}{\text { volume }}=\frac{7.05 g}{10.0 \mathrm{cm}^{3}}=0.705 \frac{g}{\mathrm{cm}^{3}} is the Answer

<u>Note:</u>

1000 g = 1 kg

100 cm = 1 m

When we used to transform the given values into S.I units, then

\text {Density}\left(\frac{k g}{m^{3}}\right)=\frac{\text {Mass}(k g)}{\text {Volume}\left(m^{3}\right)}

Alcohol’s volume can be written as, 10.0 c m^{3} = 10 \times 10^{-2} m^{3}

Alcohol’s mass can denote as, 7.05 g = 7.05 \times 10^{-3} \mathrm{kg}

Then, \text { Density }\left(\frac{k g}{m^{8}}\right)=\frac{, 00705(k g)}{0.1\left(m^{3}\right)} = .0705 \frac{\mathrm{kg}}{\mathrm{m}^{\mathrm{s}}}

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