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3 years ago

Consider the following reaction: 2{\rm{ N}}_2 {\rm{O(}}g)\; \rightarrow \;2{\rm{ N}}_2 (g)\; + \;{\rm{O}}_2 (g)

Chemistry

1 answer:

fredd [130]3 years ago

4 0

Answer:

a. 5.9 × 10⁻³ M/s

b. 0.012 M/s

Explanation:

Let's consider the following reaction.

2 N₂O(g) → 2 N₂(g) + O₂(g)

Time (t): 12.0 s

Δn(O₂): 1.7 × 10⁻² mol

Volume (V): 0.240 L

We can find the average rate of the reaction over this time interval using the following expression.

r = Δn(O₂) / V × t

r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s

r = 5.9 × 10⁻³ M/s

b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:

5.9 × 10⁻³ mol O₂/L.s × (2 mol N₂O/1 mol O₂) = 0.012 M/s

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Vlad1618 [11]

To answer this question, we will use the general gas law which states that:
PV = nRT where:
P is the pressure of the gas = 10130.0 kPa
V is the volume of the gas = 50 liters
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R is the gas constant = 8.314 L∙kPa/K∙mol
T is the temperature = 300+273 = 573 degree kelvin

Substitute with the givens in the equation to get the number of moles as follows:
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4 years ago

Consider the molecular structure for linuron, an herbicide, provided in the questions below. How many pi bonds are in the molecu

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In the herbicide linuron whose structure is shown in the image attached, there are four pi bonds.

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In the herbicide linuron whose structure is shown in the image attached to this answer, there are four pi bonds which are easily spotted as double bonds in the structure.

Learn more: brainly.com/question/7291190

6 0

3 years ago

Find the density of an object that has a mass of 6.13 g and volume of 1.50 cm³.

storchak [24]

Answer:

≈ 4.10 g/cm³

Explanation:

Hi there !

Density formula

d = m/V

d = 6.13g/1.5cm³

d = 4.08(6) g/cm³ ≈ 4.10 g/cm³

Good luck !

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3 years ago

What happens when the pressure of a gas is decreased?

Serggg [28]

Answer:

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Explanation:

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3 years ago

1. Silver nitrate will react with aluminum metal, yielding aluminum nitrate and silver metal. If you start with 0.223 moles of a

Archy [21]

Answer:

Explanation:

Given data:

Number of moles of aluminium = 0.223 mol

Mass of silver produced = ?

Solution:

Chemical equation:

3AgNO₃ + Al → 3Ag + Al(NO₃)₃

Now we will compare the moles of Al with silver.

Al : Ag

1 : 3

0.223 : 3×0.223= 0.669 mol

Grams of silver:

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Given data:

Number of moles of mercury(II) oxide produced = 3.12 mol

Mass of mercury = ?

Solution:

Chemical equation:

2Hg + O₂ → 2HgO

Now we will compare the moles of mercury with mercury(II) oxide.

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Number of moles of dinitrogen pentoxide = 12.99 mol

Mass of oxygen = ?

Solution:

Chemical equation:

2N₂ + 5O₂ → 2N₂O₅

Now we will compare the moles of N₂O₅ with oxygen.

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Mass = number of moles × molar mass

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Mass of carbon dioxide = ?

Solution:

Chemical equation:

2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O

Now we will compare the moles of N₂O₅ with oxygen.

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3 years ago