Plant trees around the perimeter of his fields
Answer:
t = 444.125 sec
Explanation:
Given data:
V = 24 volt
I = 0.1 ampere
mass of water mw = 51 gm
cr = 4.18 J/gm degree K^-1
mass of resistor = 8 gm
cr = 3.7 J/gm degree K^-1
we know that power is given as
Power P = VI
But P =E/t
so equating both side we have

solving for t


t = 444.125 sec
Answer:
A 3 feet radius snowball will melt in 54 hours.
Explanation:
As we can assume that the rate of snowball takes to melt is proportional to the surface area, then the rate for a 3 feet radius will be:
T= A(3 ft)/A(1 ft) * 6 hr
A is the area of the snowballs. For a spherical geometry is computing as:
A=4.pi.R^2
Then dividing the areas:
A(3 feet)/A(1 foot) = (4 pi (3 ft)^2)/(4 pi (1 ft)^2) = (36pi ft^2)/(4pi ft^2)= 9
Finally, the rate for the 3 feet radius snowball is:
T= 9 * 6 hr = 54 hr
That means the total of mass for the reactants needs to equal the total mass of their productions.
A.
-> the products are stable atoms with a much lower atomic number. For example, Uranium 238 commonly breaks down into strontium and xenon, both of which are stable and non-radioactive.
They are also low in quantity because of the precision involved in breaking down a large atom via neutron capture means that few fission reactions take place.
Hope I helped :)
Source: I studied nuclear physics in year 11