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Alinara [238K]
2 years ago
11

Based on the data gathered in the Rutherford's scattering experiments, the concept of atomic structure was modified. Which of th

e following aspects of the structure of the atom were validated by these experiments?
Check all that apply.
1.the charge on a proton
2.the nuclear density being large
3.most of the atomic volume being empty space
4.the existence of the atomic nucleus
5.the charge on the nucleus being positive

Which of the above apply?
Chemistry
1 answer:
Artyom0805 [142]2 years ago
6 0
The answer is 1 3 and 5 just took the test !!!!
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3.75 g of an unknown gas at 59 °C and 1.00 atm is stored in a 1.35-L flask. What is the molar mass of the gas?
MAXImum [283]
You need to find moles of the gas, so you would use the ideal gas law:
PV=nRT
Pressure
Volume
n=moles
R= gas constant
Tenperature in Kelvin
n= PV/RT
(1.00atm)(1.35L)/(.08206)(332K) = 0.050mol
Molar mass is grams per mole, so
(3.75g/.050mol) = 75g/mol
4 0
3 years ago
Which of the following contribute(s) to most of the mass of an atom?
xenn [34]

Answer:

1.

B) protons and newtrons

2.

D)

3.

C)

4.

A)

6 0
3 years ago
A gas occupies 900.0 ML at temperatures of 27.0 Celsius. What is the volume at 123.0 celsius
Artemon [7]

Answer:

1188.0 mL.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

<em>V₁T₂ = V₂T₁ </em>

V₁ = 900 mL, T₁ = 27.0°C + 273 = 300.0 K.

V₂ = ??? mL, T₂ = 123.0°C + 273 = 396.0 K.

<em>∴ V₂ = V₁T₂/T₁ </em>= (900 mL)(396 K)/(300.0 K) = <em>1188.0 mL.</em>

4 0
3 years ago
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Which unit can be used to express the concentration of a solution?
exis [7]

Answer: (3) ppm

Explanation: Concentration is defined as the amount of solute dissolved in a known amount of the solvent or  a solution.

Parts per million (ppm) is used to express the concentration when a very small quantity of solute is present in a large quantity of the solution. It is defined as the mass of solute present in one milion (10^6) parts by mass of the solution.

ppm=\frac{\text {mass of Solute}}{\text {Mass of solution}}\times 10^6

L/s is used to express flow rate.

J/g is used to express energy per unit mass.

kPa is used to express pressure.

6 0
3 years ago
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Matter appears to be conserved in chemical reactions but not in nuclear reactions because:
Vlad [161]
I think the best answer is B. Even this is the broadest case for the Conservation of matter and the one for Energy, the only way this can be applied is in nuclear rxns.
8 0
3 years ago
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