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nikdorinn [45]
3 years ago
5

An sample of an unknown metal was found in a laboratory. Determining the density of the sample can help identify what type of me

tal is present in the sample. The sample was determined to have a mass of 27.20 g when placed on a scale. When dropped in water, it increased the volume of the water by 3.46 mL. What is the density of the sample of metal?
Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
3 0
An sample of an unknown metal was found in a laboratory. Determining the density of the sample can help identify what type of metal is present in the sample. The sample was determined to have a mass of 27.20 g when placed on a scale. When dropped in water, it increased the volume of the water by 3.46 mL. What is the density of the sample of metal?
Use appropriate SIG FIGS in the answer.
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Benzene has a specific gravity of 0.88. if it was spilled in a river what would it do?
Gelneren [198K]
As we know,
                    Density of Benzene  =  876 Kg/m³
And,
                    Density of Water       =  997 Kg/m³
So,
     Specific Gravity is calculated as,

                     Specific Gravity  =  Density of Benzene / Density of Water

                     Specific Gravity    =   876 Kg/m³ / 997 Kg/m³

                     Specific Gravity    =  0.878

Every object having specific gravity less than 1 will float on water and if value is greater than 1 then it will sink.

Benzene being non-polar in nature does not mix with water and due to less density it will float on the surface of water.
4 0
3 years ago
A student has a piece of aluminum metal what is the most reasonable assumption a student can make about the metal
Gala2k [10]

Answer:

<h2>- It could be stretched into a thin wire.</h2>

Explanation:

As per the question, the most rational claim that the student can make about the aluminum metal is that 'it could be stretched into a thin wire' without breaking which shows its ductility. It is one of the most significant characteristics of a metal. Metals can conduct electricity in any state and not only when melted. Thus, option A is wrong. Options C and D are incorrect as metals neither have the same shape always nor do they break on hitting with a hammer. Therefore, <u>option E</u> is the correct answer.

3 0
3 years ago
A chemist wants to examine specific chemical reactions and isolate certain products using a controlled experiment. How would the
professor190 [17]

Answer:

in a laboratory

Explanation:

A controlled experiment refers to the one where everything is an experiment except a single variable is held constant. A collection of information is typically taken as a control group, which is generally the ordinary state, and another group is analyzed( such as chemical reaction as per the question) in which all conditions are similar to the control group except for the variable under examination. The main benefit of a controlled experiment is that confusion over the accuracy of the results can be eliminated more easily.

6 0
3 years ago
How would you know if a precipitate was formed without performing the chemical reaction
Goshia [24]
Hey there

Thats easy

Precipitation occurs when cations and anions in aqueous solution combine to form an insoluble ionic compound called precipitation. So, you can refer to a solubility chart or draw polar/nonpolar lewis structures, that might be helpful.
Remember water is polar so polar molecules will dissolve in water 
4 0
3 years ago
Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts
SOVA2 [1]

Answer:

\boxed{\text{Mg is the limiting reactant}}

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble the data in one place.

           2Mg + O₂ ⟶ 2MgO

n/mol:    2       5

Calculate the moles of MgO we can obtain from each reactant.

From Mg:  

The molar ratio of MgO:Mg is 2:2

\text{Moles of MgO} = \text{2 mol Mg} \times \dfrac{\text{2 mol MgO}}{\text{2 mol Mg}} = \text{2 mol MgO}

From O₂:  

The molar ratio of MgO:O₂ is 2:1.

\text{Moles of MgO} = \text{5 mol O}_{2} \times \dfrac{\text{2 mol MgO}}{\text{1 mol O}_{2}} = \text{10 mol MgO}\\\\\boxed{\textbf{Mg is the limiting reactant}} \text{ because it gives the smaller amount of MgO}

6 0
3 years ago
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