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andrey2020 [161]
3 years ago
11

How many grams of sodium nitrate are needed to make 2.50L of 1.12m solution ​

Chemistry
1 answer:
Roman55 [17]3 years ago
7 0

Answer:  238 g of sodium nitrate are needed to make 2.50L of 1.12m solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Now put all the given values in the formula of molality, we get

1.12=\frac{\text {moles of}NaNO_3}{2.50}

moles of NaNO_3 = 2.8

moles of NaNO_3=\frac{\text {given mass}}{\text {Molar mass}}

2.8mol=\frac{xg}{85g/mol}

x=238g

Thus 238 g of sodium nitrate are needed to make 2.50L of 1.12m solution ​

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47.2 moles Na           2 moles NaCl              58.44 grams

----------------------  x  ---------------------------  x  -------------------------  =
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