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Irina-Kira [14]
3 years ago
12

• List two conditions needed for transfer of heat by conduction

Physics
2 answers:
Murljashka [212]3 years ago
7 0

Answer:

Difference in temperature

Contact between the bodies

ZanzabumX [31]3 years ago
3 0
The two conditions that are required for the conduction of heat are:
1) passing method
2) movement method
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According to the law of universal gravitation, any two objects are attracted to each other. The strength of the gravitational fo
hodyreva [135]

Answer:

C. Plant A orbits its star faster than Plant B

Explanation:

Did it on study island

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2 years ago
An auditorium measures 43.0m × 18.0m × 15.0m. The density of air is 1.20 kg/m3. What is the volume of the room in cubic feet? (D
frez [133]
The question here would be what is the volume of the room. The density of air that is given has no use. We simply multiply the dimensions given of the room to determine  the volume.

<span>43.0m × 18.0m × 15.0m = 11610m^3 ( 3.28 ft / 1 m)^3 = 4.09 x 10^5 ft^3</span>
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2 years ago
A long thin uniform rod of length 1.50 m is to be suspended from a frictionless pivot located at some point along the rod so tha
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Answer:

0.087 m

Explanation:

Length of the rod, L = 1.5 m

Let the mass of the rod is m and d is the distance between the pivot point and the centre of mass.

time period, T = 3  s

the formula for the time period of the pendulum is given by

T = 2\pi \sqrt{\frac{I}{mgd}}    .... (1)

where, I is the moment of inertia of the rod about the pivot point and g is the acceleration due to gravity.

Moment of inertia of the rod about the centre of mass, Ic = mL²/12

By using the parallel axis theorem, the moment of inertia of the rod about the pivot is

I = Ic + md²

I = \frac{mL^{2}}{12}+ md^{2}

Substituting the values in equation (1)

3 = 2 \pi \sqrt{\frac{\frac{mL^{2}}{12}+ md^{2}}{mgd}}

9=4\pi^{2}\times \left ( \frac{\frac{L^{2}}{12}+d^{2}}{gd} \right )

12d² -26.84 d + 2.25 =  0

d=\frac{26.84\pm \sqrt{26.84^{2}-4\times 12\times 2.25}}{24}

d=\frac{26.84\pm 24.75}{24}

d = 2.15 m , 0.087 m

d cannot be more than L/2, so the value of d is 0.087 m.

Thus, the distance between the pivot and the centre of mass of the rod is 0.087 m.

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What is the main function of a telescope?
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It magnifies light received from distant objects.
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