An object with an initial speed of 4.0 m/s accelerates uniformly at 2.0 m/s^2
in
As per the question, the resistor system contains two resistors.
The two resistors are denoted as 
We are asked to calculate the effective resistance in terms of
The two resistors can be connected in two ways.
CASE-1: Let the resistors are connected in series.
When the resistors are connected in series, the effective resistance is the algebraic sum of the individual resistors.
Hence, the effective resistance 
[ans]
CASE-2: Let the resistors are connected in parallel.
The effective resistance is calculated as follows-
⇒ 
[ans]
Answer:
(-1.5,-1.5)m
Explanation:
we know that:
where 
is the location of the center of gravity in the axis x, 
is the mass of the object i and 
the first coordinate of center of gravity of object i.
so:
Where 
is the first coordinate of the center of gravity for the fourth object.
Therefore, solving for , we get:
At the same way:
where 
is the location of the center of gravity in the axis y, is the mass of the object i and 
the second coordinate of center of gravity of object i. replacing values we get:
Where 
is the second coordinate of the center of gravity for the fourth object.
solving for :
It means that the object of mass 8kg have to be placed in the
coordinates (-1.5,-1.5) m.
Answer:
τ = (7.96 x 10⁴ m⁻³)T
This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.
Explanation:
The maximum allowable shear stress on the solid shaft can be given by the torsional formula as follows:
τ = Tc/J
where,
τ = Maximum Allowable Shear Stress = ?
T = Maximum Torque Applied to the Shaft
c = maximum distance from center to edge = radius in this case = 20 mm = 0.02 m
J = Polar Moment of inertia = πr⁴/2 = π(0.02 m)⁴/2 = 2.51 x 10⁻⁷ m⁴
Therefore,
τ = T(0.02 m)/(2.51 x 10⁻⁷ m⁴)
<u>τ = (7.96 x 10⁴ m⁻³)T</u>
<u>This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.</u>
Work done = force * distance moved (in direction of the force)
force= mass* acceleration
force=58.1N
58.1*(5.8*10^4)
=3,369,800 J
