The answer is: "
44
km " ;
or; write as: "
44.333 km " .
___________________________________________________________Explanation:___________________________________________________________(70 km + 63 km) ÷ (2 + 1 ) = 133 km ÷ 3 = "
44
km " ;
or; write as: "
44.333 km " .
___________________________________________________________
Speed of a wave is in m * s-1, so we can figure this out through process of elimination to make the units of Tension and mass/length equal our goal units of m/s.
First, we can see there are no kg in our result, so no matter what we have to have F/μ or μ/F so we get our kg to cancel out.
Now we are left with either:
![\frac{F}{u} = \frac{m}{s^{2} } * \frac{1}{\frac{1}{m}} = \frac{m}{s^{2} } * \frac{m}{1} = \frac{m^{2}}{s^{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7BF%7D%7Bu%7D%20%3D%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%20%2A%20%5Cfrac%7B1%7D%7B%5Cfrac%7B1%7D%7Bm%7D%7D%20%3D%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%20%2A%20%5Cfrac%7Bm%7D%7B1%7D%20%3D%20%5Cfrac%7Bm%5E%7B2%7D%7D%7Bs%5E%7B2%7D%7D%20)
/F
or
![\frac{u}{F} = \frac{1}{m } * \frac{1}{\frac{m}{s^{2} }} = \frac{1}{m} * \frac{s^{2}}{m } = \frac{s^{2}}{m^{2}} ](https://tex.z-dn.net/?f=%5Cfrac%7Bu%7D%7BF%7D%20%3D%20%5Cfrac%7B1%7D%7Bm%20%7D%20%2A%20%5Cfrac%7B1%7D%7B%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%7D%20%3D%20%5Cfrac%7B1%7D%7Bm%7D%20%2A%20%5Cfrac%7Bs%5E%7B2%7D%7D%7Bm%20%7D%20%3D%20%5Cfrac%7Bs%5E%7B2%7D%7D%7Bm%5E%7B2%7D%7D%20%0A%0A)
Now if our goal is m/s, the former of F/μ is closer, but off by a square. If we correct that by squaring F/μ we get
Answer:
At twice the distance, the strength of the field is e/4
Explanation:
F = the strength of an electric field.
F is inversely proportional to the squared distance from the point charge.
mathematically,
F = k(e/d²)
hence, if d is doubled,keeping other forms constant
F = e/4,
Answer:
Explanation:
capacitance of capacitor
= ε₀ A / d , A is area of plate , d is plate separation
= (8.85 x10⁻¹² x 1.7² x 10⁻⁴) /( .35 x 10⁻³ )
= 73 x 10⁻¹³ F
Charge = 4.5 x 10⁻⁷
voltage between the plates,
Δ V = charge / capacitance
= 4.5 x 10⁻⁷ / 73 x 10⁻¹³
= .0616 x 10⁶
= 616 x 10² V
To make the vottage double , we will reduce capacitance to half .
To reduce capacitance half we will increase plate distance to double.
new plate distance
= 1.7 x 2
= 3.4 cm
For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as
du=0.2512J
<h3>What is the largest potential energy difference (in Joules) you can find between two orientations?</h3>
Generally, the equation for the initial velocity is mathematically given as
v0=-iAB
Therefore
-2*\pi(0.2)(0.5))
v0=-0.1256J
for 180
theta=0180=-iABcos180
V180=0.1256J
Therefore
du=v180-v0
0.1258-(-0.1256
du=0.2512J
In conclusion, potential energy
du=0.2512J
Read more about Energy
brainly.com/question/13439286